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$\begingroup$

I'm an important figure in my field. Who am I?

-----------------------------------------------
|   seat    |    heat   |   fish    |   line  |
|---------------------------------------------|
|    go     |    beat   |   music   |  lunch  |
|---------------------------------------------|
|  grumpy   |    end    |   sand    |   nap   |
|---------------------------------------------|
|   lock    |   stock   |  stream   |   walk  |
-----------------------------------------------
$\endgroup$

1 Answer 1

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Groups:

CAT: grumpy, fish, nap, walk
LIVE: music, go, stock, stream
DEAD: heat, line, end, lock
BOX: seat, lunch, sand, beat

(Originally I had deadbeat and lockbox which also fits, but the intended solution was deadlock and beat box).

Pointing to:

Schrodinger's cat, the thought experiment in quantum physics about a cat in a box that could simultaneously be alive and dead. Which means the answer is Erwin Schrodinger, the Nobel winning physicist who invented Schrodinger's cat.

Title refers to:

Quantum mechanics, which is normally used in micro systems, being theoretically valid (though computationally impractical) for macroscopic systems. (From Aaron Hayman in comments)

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    $\begingroup$ Nice. Minor point though, the final answer should be a name since the question is 'Who am I?'. That'll be enough :) But, optionally, if you want to explain the title, that'd be fun. $\endgroup$
    – Luke
    Commented Oct 6, 2019 at 12:59
  • $\begingroup$ You inverted rot13(ORNGOBK naq QRNQYBPX). $\endgroup$ Commented Oct 6, 2019 at 15:19
  • $\begingroup$ @ArnaudMortier it works the way I have it too rot13(qrnqorng naq ybpxobk), but I guess the OP has to say. $\endgroup$
    – JS1
    Commented Oct 6, 2019 at 16:21
  • $\begingroup$ @JS1 I initially made it like what Arnaud said. But your answer is also valid and right. What you're pointing at is also right. But the final answer should be the name of the person, mate. That way I can accept the answer. $\endgroup$
    – Luke
    Commented Oct 6, 2019 at 17:00
  • $\begingroup$ @Luke sorry I didn't have enough time earlier to fix my answer. $\endgroup$
    – JS1
    Commented Oct 6, 2019 at 19:14

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