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This puzzle was inspired by this one

Who will be the first to solve this tricky math crossword puzzle completely?

Blank Crossword Grid

Across

2: Half of ({20 Across} x (smallest perfect number) + 446)
3: (Number of essentially different positions in the most popular futile game) x (only square that is one more than a prime number) - (number of cents in two quarters)
6: Radius of a circle with circumference = 18,881 (rounded to nearest integer)
8: Equals 500 + (x times y), where $3x + 2y = 120$ and $x - 5y = -215$
9: (Distance around an octagon with side = ((a perfect score in bowling) + (a baker's dozen))) + (number of even primes)
10: Opposite of ((basis of percentages) - ((double factorial of 10) - (the least common multiple of 1, 2, 3, 4, 5, 6, 7, 8)))
13: The Bin2Dec of 10001000011
14: (Every number from 1 to 100 added together) - (Floor(Year(Now()),100))
16: (Opposite of (sum of the first nine prime numbers)) + ((1130 in octal)$^2$/100)
17: Miles that equal 1915 km (rounded to the nearest integer)
19: (Number of ways to order a burger with 10 possible toppings) + (sum of the first four squares)
20: (Double any angle in an equilateral triangle) x (smallest integer which is neither prime nor semiprime) + (atomic # of Einsteinium)
21: (Opposite of where Fahrenheit = Celsius) x (sum of the squares of the first four primes) + (Michael Jordan's famous number)

Down

1: Weighted average of 1000 and 2000 where 2000 is weighted at 70% and 1000 is weighted at 30%.
2: Equals {19 Down} x (smallest prime number) + (latitude in degrees of the North and the South geographical poles)
4: (Inches in a foot) x (5B in hex) + (number of non-collinear points needed to determine a plane)
5: (Number of distinct Hamiltonian paths from cell A1 to cell A4 in a 4 x 4 grid) x (column ED in spreadsheet notation) - (basis of duality)
6: (Opposite of an even prime number) + (number of ways to choose 10 things from 15 things (without repetition))
7: Multiply (smallest sphenic number) and (4 score + (number of platonic solids))
11: Area of a rectangle with sides (sum of the first four pentagonal numbers) and (number of degrees in a right angle)
12: (Six factorial) x (number of triangle sides) - (twin prime of 149)
13: (Hypotenuse length of right triangle with sides 300 and 400) x (smallest composite number) - (number of states in the USA)
15: ((Rhombus edge count) x (dodecahedron edge count) x ((number of ways 4 items can be arranged) + 5)) + (number of hours in a day)
18: (All the values in an order-3 magic hexagon added together) - (smallest number that is the sum of two non-zero square numbers in two distinct ways)
19: Subtract (median of the set (77,81,94,96,98,99)) from (highest number expressible using only two unmodified characters in Roman numerals)

Hint #1:

The clue for the twist part is among the clues. Your work up to this point will not be in vain, but will need to have the twist applied to it.

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2 Answers 2

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Everything fits:

enter image description here

Text version of the answer:

    ................M
............MMMCD
....MMMX....M...C
......X.M.MMMV..C
....M.CML.M.C....
...MMDV.X.M.MMCM.
..M.D..MXCI....M.
.MMML..C....M..M.
..I....M....MMMD.
MCXC..MLIV..M..C.
.X....C.....D....
XLIX..M.MMMDIII..
......V.....V....

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  • $\begingroup$ I apologize about 16 across. Apparently I cannot properly square 600. It is corrected now. Good job! $\endgroup$
    – JLee
    May 14 at 0:47
  • $\begingroup$ Rot13: Qvq lbh svaq gur uvqqra pyhr, be qvq lbh whfg gel Ebzna ahzrenyf? $\endgroup$
    – JLee
    May 14 at 0:59
  • $\begingroup$ I don't recall how I figured it out. Was 19D supposed to be the clue, or was there another hint? $\endgroup$ May 14 at 11:54
  • $\begingroup$ rot13: Gur svefg yrggref bs rnpu pyhr fcryy n uvag jura chg va ahzrevpny beqre, npebff svefg gura qbja jura n ahzore vf va obgu. $\endgroup$
    – JLee
    May 14 at 12:27
2
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Missing the main twist right now, meaning some answers don't fit in the grid.

This is what I have so far:

enter image description here

Answers and working - some don't fit the grid:


Across

2: Half of ({20 Across} x (smallest perfect number) + 446)

(1059 * 6 + 446)/2 = 3400 - doesn't fit

3: (Number of essentially different positions in the most popular futile game) x (only square that is one more than a prime number) - (number of cents in two quarters)

765 (tic-tac-toe) * 4 - 50 = 3010

6: Radius of a circle with circumference = 18,881 (rounded to nearest integer)

18,881 / 2π = 3005

8: Equals x times y, where $3x + 2y = 120$ and $x - 5y = -215$

x = -215 + 5y, 3(-215 + 5y) + 2y = 120
-645 + 17y = 120, 17y = 765
y = 45, x = 10, xy = 450
450 + 500 = 950

9: (Distance around an octagon with side = ((a perfect score in bowling) + (a baker's dozen))) + (number of even primes)

Side length = 300 + 13 = 313
Answer = 8 * 313 + 1 = 2504 + 1 = 2505

10: Opposite of ((basis of percentages) - ((double factorial of 10) - (the least common multiple of 1, 2, 3, 4, 5, 6, 7, 8)))

- ((100) - ((3840) - (840))) = 2900 - fits?

13: The Bin2Dec of 10001000011

Using online converter: 1091

14: (Every number from 1 to 100 added together) - (Floor(Year(Now()),100))

5050 - 2000 = 3050

16: (Opposite of (sum of the first nine prime numbers)) + (1130 in octal)$^2$

(-(100)) + ((600)^2/100) = 3600 - 100 = 3500 -doesn't fit

17: Miles that equal 1915 km (rounded to the nearest integer)

1915 km = 1189.9 miles = 1190

19: (Number of ways to order a burger with 10 possible toppings) + (sum of the first four squares)

1023 + 30 = 1053 - 1 off

20: (Double any angle in an equilateral triangle) x (smallest integer which is neither prime nor semiprime) + (atomic # of Einsteinium)

(2*60) * 8 + 99 = 960 + 99 = 1059

21: (Opposite of where Fahrenheit = Celsius) x (sum of the squares of the first four primes) + (Michael Jordan's famous number)

- (-40) * 87 + 23 = 3480 + 23 = 3503 - doesn't fit?


Down

1: Weighted average of 1000 and 2000 where 2000 is weighted at 70% and 1000 is weighted at 30%.

1000 x 0.3 + 2000 * 0.7 = 1700

2: Equals {19 Down} x (smallest prime number) + (latitude in degrees of the North and the South geographical poles)

1905 * 2 + 90 = 3900

4: (Inches in a foot) x (5B in hex) + (number of non-collinear points needed to determine a plane)

12 * 91 + 3 = 1095

5: (Number of distinct Hamiltonian paths from cell A1 to cell A4 in a 4 x 4 grid) x (column ED in spreadsheet notation) - (basis of duality)

8 * 134 - 2 = 1070

6: (Opposite of an even prime number) + (number of ways to choose 10 things from 15 things (without repetition))

(-2) + 3003 = 3001

7: Multiply (smallest sphenic number) and (4 score + (number of platonic solids))

30 * (80+5) = 2550

11: Area of a rectangle with sides (sum of the first four pentagonal numbers) and (number of degrees in a right angle)

40*90 = 3600

12: (Six factorial) x (number of triangle sides) - (twin prime of 149)

6! * 3 - 151 = 720*3 - 151 = 2009

13: (Hypotenuse length of right triangle with sides 300 and 400) x (smallest composite number) - (number of states in the USA)

500*4 - 50 = 1950

15: ((Rhombus edge count) x (dodecahedron edge count) x ((number of ways 4 items can be arranged) + 5)) + (number of hours in a day)

((4)*(30) * ((24)+5)) + (24) = 3504 - doesn't fit

18: (All the values in an order-3 magic hexagon added together) - (smallest number that is the sum of two non-zero square numbers in two distinct ways)

190 - 50 = 140

19: Subtract (median of the set (77,81,94,96,98,99)) from (highest number expressible using only two unmodified characters in Roman numerals)

2000 - 95 = 1905

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  • $\begingroup$ Please correct me on any poor maths, or if I'm missing a twist somewhere :) $\endgroup$ May 11 at 23:24
  • $\begingroup$ @JLee had a feeling I might be, a 4/9 typo sure, but I assumed the rest was twisted somehow, I'll see if I can find it! $\endgroup$ May 12 at 0:08
  • $\begingroup$ @JLee double checking 19, 1 more or 1 less than what it should be? I've included the option of choosing no toppings when ordering the burger $\endgroup$ May 12 at 0:17
  • $\begingroup$ Great job so far. +1 Just a a few things: 1. Make a couple corrections, 2. Find the twist clue, and 3. Apply it. $\endgroup$
    – JLee
    May 13 at 12:28
  • $\begingroup$ I'm sorry that 16A had an error. It is corrected now. $\endgroup$
    – JLee
    May 14 at 0:46

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