Introducing Domidoku!

Question

Come one, come all!
Come see the new type of logic puzzle, the Domidoku!

Here's a sample for all to try!

The process is simple!
First you solve the Sudoku and then you solve the Dominosa!

Clarification on Dominosa (the part everyone's confused on):
You must group all the numbers into pairs so that all the unique domino pieces show up once. (except the doubles and the zeros since it's also sudoku)
i.e. 1-2 through 8-9 will all show up once and only once. No more, no less.

^{Disclaimer: I am not responsible for any injuries, be they physical or mental, that occur while solving this puzzle.}

Answer 1

I worked with @Techidiot's sudoku solution and solved the Dominosa:

The key to understand is that unlike regular Dominosa there are no tiles with same digits. and the grey cells indicate cells that shouldn't be included in the solution

Answer 2

Final Solution(Though its already answered, I wanted to solve it on my own as a part of learning. Due to an ongoing problem with imgur, it took too long for uploading the solution)

SUDOKU Solution.

Updated Better solution

Upon observing we get to know that, 5-8, 6-7 and 9-7 are unique. And we get ahead like this

Solution(Getting the idea from Ivo about the marked spots in the puzzle)

I am a novice to Grid puzzles and have specified all the steps I took while solving ...

1. We can simply fill 3-5 block just by looking.




2. I did a bit of a trial and errors, and I came up with the next cell as 3-9.





3. Now, that we have 3-5 and 3-9, we can cross of 3-4 at the bottom as there is no other way to go



4. Since we have 9-3 pair, we can cross off 9-4 at the top




5. Which gives 9-2 as well.



6. Now, we have 9-3, 9-4, we get 9-8 as a new pair



7. Also, we get 9-1.



8. And then similarly, 9-6, 9-7, 9-5, 2-5, 4-7, 1-8


9. Now, as we already have 3-4, we get 4-2 as a new pair



10. Also, we already have 2-5, so we can knock off 5-1, 2-6,8-7(dead ends)



11. We have 8-7 and 7-4, so we get 7-5 as a new pair. Also, we can knock off 7-3, 8-6 at the top right.



12. We already have 7-4, 7-3, so we can knock off 7-6 which also gives 3-8, 5-4, 2-3 as dead ends



13. Now, we have 8-7, 8-3, so we can knock off 8-4 which also gives 1-6, 3-6 as dead ends



14. We already have 8-4, so we can knock off 4-1 which also gives 8-2, 6-5 as dead ends



15. Now that we have 1-8 already, we can get 1-7 and then 1-3 at the top. Which gives 7-2, 6-4, 5-8, 1-2 as dead ends and completes the Domidoku.




BRAVO!!

Answer 3

Here is is. I hope I understood the rules of Dominosa.
I used my awesome Pinta skills to solve this.

Some of them are 2x2 squares instead of 1x2 rectangles because you can arrange 2 domino pieces in any position in those squares.

For sudoku I started from the top left 3x3 square. It is obvious where you can place an 8 and took it from there.
At one point, I admit, I took 2 leaps of faith and got it right for both of them.
For domino tiles, I tried to start from the bottom left corner. It's obvious that 3x5 go together. Then started incrementally 1x2, 1x3 and so on until something fit. Then some things became obvious.

Off topic a bit.

First I checked if this is not a trick question.
I tried first to see if the board can be covered by dominos like this.
Consider it as a chess board (9x9) where the top right corner is white.
This means 41 white squares and 40 black ones.
Then counted the blocked squares. I got 5 white and 4 black.
This means I have to place domino pieces on 72 squares where 36 are white and 36 are black. Since a domino piece covers a white and a black square, this is doable.