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I know the concept of pairing and removed pairs but what other concepts should I use to solve this?

  • $\begingroup$ You could try guessing and check if it works in your mind, like when there are two possibilities, like in the bottom right square. $\endgroup$ – Duck Oct 7 '19 at 16:23

There is only one place to put

a 6 in column 1

followed by the

6 in row 6

  • $\begingroup$ Could you add a rationale? $\endgroup$ – 030 Oct 14 '19 at 17:54
  • $\begingroup$ @030 Is it not obvious? There is only one cell in the first column that still contains a small 6. $\endgroup$ – Jaap Scherphuis Oct 14 '19 at 17:57

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