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How many pieces can you organize on a Chess board without one side being attacked by the other? This scoring will be used to prove you have the highest.

Piece cost:

  • Pawn - 1
  • Knight - 3
  • Bishop - 3
  • Rook - 5
  • Queen - 9

Rules:

  • Both sides must have the same pieces on the board
  • Your score is totalled by only 1 side
  • One color cannot attack the other
  • No king allowed.
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  • 1
    $\begingroup$ Is there restriction on the number of pieces of each type that can be used? If not, the eight queens should be the baseline, scoring 36. $\endgroup$
    – LeppyR64
    Commented Oct 14, 2014 at 22:52
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    $\begingroup$ There is no restriction on pieces. $\endgroup$
    – warspyking
    Commented Oct 14, 2014 at 23:04

2 Answers 2

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15
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From the bottom up:

Three rows of 8 black queens
One row of black pawns
One row of white pawns
Three rows of white queens

224.

Because the black pawns attack down and the white pawns attack up, they can be placed next to each other without attacking each other.

224 Points

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9
  • $\begingroup$ Can you provide a picture? $\endgroup$
    – warspyking
    Commented Oct 14, 2014 at 23:57
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    $\begingroup$ Here you go. $\endgroup$
    – user88
    Commented Oct 15, 2014 at 0:05
  • $\begingroup$ The pawns attack eachother in your answer. $\endgroup$
    – warspyking
    Commented Oct 15, 2014 at 0:50
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    $\begingroup$ @warspyking white moves up the board, so the black pawns are behind them meaning they can't attack $\endgroup$
    – Joe
    Commented Oct 15, 2014 at 0:55
  • $\begingroup$ Oh... I guess that makes sense. $\endgroup$
    – warspyking
    Commented Oct 15, 2014 at 1:06
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Although I like my first answer, I did also wonder how good I could manage with black and white in their normal positions. The best I've gotten so far uses 16 queens, 4 rooks, 4 bishops and 4 pawns.

180.

180 Points

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7
  • $\begingroup$ I believe you can change D6 -> black pawn, E3 -> white rook, E4 -> white pawn to gain 3 points $\endgroup$
    – Joe
    Commented Oct 15, 2014 at 15:30
  • $\begingroup$ @Joe Both sides must have same pieces. White would have 1 more rook than black. $\endgroup$
    – Joel Rondeau
    Commented Oct 15, 2014 at 15:33
  • $\begingroup$ Ah, I forgot the same-pieces argument. How very dull. $\endgroup$
    – Joe
    Commented Oct 15, 2014 at 15:36
  • $\begingroup$ Yeah, I know. Without it, I'm pretty sure I could manage 576. $\endgroup$
    – Joel Rondeau
    Commented Oct 15, 2014 at 15:40
  • $\begingroup$ @Joel You know the white side can have black pieces right? $\endgroup$
    – warspyking
    Commented Oct 15, 2014 at 19:43

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