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Rule 1: There are no rules

Rule 2: When in doubt, see rule 1

The puzzle is to find the next two items in the following sequence:

D15 R0 D22 R13 R-13 D11 ...

Hints

  1. This puzzle is related to something "in the real world". If you are looking for a purely mathematical way to solve this you are on the wrong path.
  2. This puzzle has to do with American Politics.
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    $\begingroup$ I have an idea about this - I don't think it's impossible, but it is potentially extremely tedious $\endgroup$
    – question_asker
    Commented Jan 27, 2016 at 20:38
  • $\begingroup$ This is not a riddle or a logic puzzle; please look at tag descriptions before using them. $\endgroup$
    – Deusovi ♦
    Commented Jan 28, 2016 at 4:03
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    $\begingroup$ Is the - in R-13 put there intentionally? $\endgroup$
    – Verzweifler
    Commented Jan 28, 2016 at 8:52
  • $\begingroup$ @f'' - I noticed the same, but assumed it was reverse order, from current. So: Obama (D), Bush (R), Clinton (D), Bush (R), Reagan (R), Carter (D). Possibly making the next two Ford (R) & Nixon (R)... $\endgroup$
    – Alconja
    Commented Jan 29, 2016 at 1:45
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    $\begingroup$ @question_asker - I don't know enough US politics to take it further (nor the patience to research), but was thinking the numbers could be some sort of statistic from while that person was in office (eg. % national debt increase, change in number of bills approved, etc), which would allow for negatives. $\endgroup$
    – Alconja
    Commented Feb 15, 2016 at 14:53

1 Answer 1

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D donates Double, R is Reverse. solve the puzzle as a mirror in the middle.

Take Reverse -13 to 13. Double 11 to 22. so x= R0, y=D7.5

at least this one makes sense to me :)

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  • $\begingroup$ How do you know Y isn't D30? $\endgroup$
    – GentlePurpleRain
    Commented Jan 21, 2016 at 13:01
  • $\begingroup$ because the right hand side numbers are reflected according to the symbol on their left. It could be the other side, but the reflection works for all numbers and symbols given at least. This may not be the answer but the logic makes sense at least. $\endgroup$
    – Oray
    Commented Jan 21, 2016 at 13:04

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