6
$\begingroup$

When the day after tomorrow becomes yesterday,
the day which would then be today will be as far from Sunday as the day which is yesterday when it's two days after that day's tomorrow.

What day of the week was this spoken?

$\endgroup$

3 Answers 3

4
$\begingroup$

The answer is

Wednesday

Explanation:

When the day after tomorrow becomes yesterday,

Three days from now (A)

the day which would then be today will be as far from Sunday as

the day which is yesterday when it's two days after that day's tomorrow.

Two days after that day.(B) A and B are two days apart and equally far from Sunday, so they must be Saturday and Monday, meaning the original day was Wednesday.

$\endgroup$
3
$\begingroup$

This statement was spoken on

a Wednesday.
Day after tomorrow becomes yesterday on Saturday. And Saturday is 1 day away from Sunday.
Monday would be yesterday when it's Tuesday, which is two days after Sunday(which is Saturday's tomorrow).

And both Saturday and Monday are equidistant from Sunday.

An explanation to my strategy:

Consider our day of speaking to be Xday. We have two days of interest. First is that day on which day after tomorrow becomes yesterday which is the (X+3)th day. The second is yesterday when it is two days after (X+3)th day's tomorrow. Which is (X+3+1+2-1)th or (X+5)th day.

Writing down the week with Sunday as the centre, we can only choose Saturday and Monday as the days of interest. Hence, Wednesday has to be our Xday.

$\endgroup$
0
$\begingroup$

It is Sunday.as Day after tomorrow is Tuesday and Tuesday becomes yesterday on Wednesday, so Wednesday is 2 days away( Go backwards, so we have only Monday and Tuesday in between Wednesday and Sunday). Then as day before yesterday would be Friday and Friday would be tomorrow on Thursday. So again Thursday is 2 days away ( Go forward, so we have only Friday and Saturday in between Thursday and Sunday)

$\endgroup$
1
  • 2
    $\begingroup$ Welcome to the site! But since the correct answers above all say Wednesday, I think there must be an error in your logic somewhere. $\endgroup$ Commented Mar 2, 2020 at 9:18

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service and acknowledge you have read our privacy policy.

Not the answer you're looking for? Browse other questions tagged or ask your own question.