8
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This is a word division puzzle which uses cryptic clues. If you're unfamiliar with either or both of those, you can click the associated link.

In order to solve the alphametic, you'll first need to fill in the dividend, divisor, and quotient by solving the cryptic clues. I've left the enumerations off to provide a bit of extra challenge. Once you fill those in, the puzzle should be solvable with only arithmetic and logic. The solution is a 10-letter word or phrase found by ordering the letters from 0 through 9. A complete answer should provide this solution along with explanations of the cryptic clues and your path through the alphametic.

As always, I've created an interactive version that will autofill from the grid to the clues and vice versa. Have fun!

Clues:

  • House is haunted - a phantom's turned up inside
  • Trapping you and I in eternal, fiery pits? It's the greatest of Satan's tricks
  • Ritual involving the drinking of blood with supernatural entities in the end roaming free, leaving behind widespread carnage

Accessible version:

           ???
      --------
?????|????????
      MUSSCM  
      ------  
       CJJUPR 
       SMEDJS 
       ------ 
        RUMPPE
        ASPPCA
        ------
         AEDEM
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1 Answer 1

8
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Confession: I solved this almost exactly backwards: I looked at the letters, guessed what the 10-letter word or phrase would be, looked at individual products, deduced what the 5-digit and 3-digit numbers (and hence words) had to be, and used that to check the suspicion I had (without having fully solved the clue) for the 8-letter word. But I'll do things forwards here :-).

Clues

House is haunted -- a phantom's turned up inside

PAD. "House" is def and PAD is a reversed substring of "haunted -- a phantom".

Trapping you and I in eternal, fiery pits? It's the greatest of Satan's tricks

RUSES. "Tricks" is def. US (you and I) is trapped in RES, which is the centres ("pits") of eteRnal and fiEry, plus S (the greatest of "Satan").

Ritual involving the drinking of blood with supernatural entities in the end roaming free, leaving behind widespread carnage

MASSACRE. "Carnage" is def. MASS (ritual involving the drinking of blood) with ACRE, which is SACRED (supernatural, kinda) with S ("entities" in the end) roaming free, and D (behind "widespread") leaving.

(Those were unusually convoluted...)

*Alphametic

                      P A D
          _________________
R U S E S ) M A S S A C R E
            M U S S C M
            -----------
              C J J U P R
              S M E D J S
              -----------
                R U M P P E
                A S P P C A
                -----------
                  A E D E M

First, notice that

A-U=C, with no borrow (first subtraction, near the left), so C < A, so there's no borrow from A-C near the right of the first subtraction, so when we see S-S=J that means J=0. So the P-J=P near the right of the second subtraction means that there's no borrow from the column to its right, so R > S.

Also,

C-S and R-A both yield zero, obviously with borrows, so C = S+1 and R = A+1. So we have SC and AR in our final 10-letter word or phrase, which I am pretending I don't know yet. And the previous observation says that SC comes before AR.

Current state of play:

                      P A D
          _________________
R U S E S ) M A S S A C R E
            M U S S C M
            -----------
              C 0 0 U P R
              S M E D 0 S
              -----------
                R U M P P E
                A S P P C A
                -----------
                  A E D E M

0 1 2 3 4 5 6 7 8 9
J

answer: J...SC...AR...

Now another easy observation:

we already saw that A-U=C and hence A-C=U, so the column saying as much near the right of the first subtraction doesn't have a borrow into it, so M+P=C. In particular, M,P both come between J and SC in our word-or-phrase. Also, look at the last subtraction: we have P-P=D (not J), so we must have D=9.

                      P A 9
          _________________
R U S E S ) M A S S A C R E
            M U S S C M
            -----------
              C 0 0 U P R
              S M E 9 0 S
              -----------
                R U M P P E
                A S P P C A
                -----------
                  A E 9 E M

0 1 2 3 4 5 6 7 8 9
J                 D

answer: J...{M,P}...SC...AR...D

At this point we have

either something like JMPSCARD or something like JPMSCARD

and it's getting increasingly difficult to keep up the pretence of not knowing the final answer, but let's proceed. Look at

the second subtraction, where we have P-0=P (clearly no borrow), then U-9=M (so clearly M=U+1 and there's a borrow propagating left from there), then 0-E(-1)=U (since we have MSCARD to the right of U, we have U<=3, so E=9-U>=6. After that (borrow still propagating left) we have 0-M(-1)=R; we have JUMPSCA to the left of R so R >= 7, so M=9-R <= 2. But we also have JU to the left of M, so M >= 2. So we can lock in JUM as 012 and and hence RE=78. And remember that we know A=R-1.

                      P 6 9
          _________________
7 1 S 8 S ) 2 6 S S 6 C 7 8
            2 1 S S C 2
            -----------
              C 0 0 1 P 7
              S 2 8 9 0 S
              -----------
                7 1 2 P P 8
                6 S P P C 6
                -----------
                  6 8 9 8 2

0 1 2 3 4 5 6 7 8 9
J U M       A R E D

answer: JUM...P...SC...ARED

But wait,

that only leaves three spaces for P,S,C which have to come in that order, suddenly and shockingly revealing that the answer is JUMP-SCARED.

                      3 6 9
          _________________
7 1 4 8 4 ) 2 6 4 4 6 5 7 8
            2 1 4 4 5 2
            -----------
              5 0 0 1 3 7
              4 2 8 9 0 4
              -----------
                7 1 2 3 3 8
                6 4 3 3 5 6
                -----------
                  6 8 9 8 2

0 1 2 3 4 5 6 7 8 9
J U M P S C A R E D

answer: JUMPSCARED

It's interesting that this was solved using only the subtractions -- we didn't need to look at the multiplications at all!

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2
  • $\begingroup$ yeah, the clues were a little bit more convoluted than usual this time, because complicated things are scary! (and also because I pivoted last minute from a much more fun, upbeat clue for the divisor to lean more into the horror aspect, so I probably could've done better.) for the record, I did have a less-convoluted parsing in mind for the dividend, which was that {"ragvgvrf va gur raq" ersreerq gb gur ynfg yrggref bs obgu ZNFF naq FNPERQ, naq gur nafjre jnf jung gurl yrsg oruvaq} $\endgroup$
    – juicifer
    Commented Nov 1 at 1:39
  • $\begingroup$ in any case, great answer as always! I like being able to almost walk through your solving process with you $\endgroup$
    – juicifer
    Commented Nov 1 at 1:40

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