Unfinished Snakes and Ladders

Question

_{An entry for Fortnightly Topic Challenge #40, have fun with non-Chess puzzle! ;)}

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Three young children: Red, Green, and Blue; were playing a classic game of Snakes and Ladders, when suddenly their mom called them to have a dinner.

When they came back to their room, they forgot whose turn it was; even they were not sure either about the order of the play!

This was the last condition of the board, including the die. Could you tell them whose turn it is and the order of the play?

Some notes and clarifications:

• They put their markers at tile 1, at the beginning.
• They will win if their markers land exactly on tile 100. They are using the "bouncing-back" version (roll 3 will move the marker from tile 99 to 98).
• As long as they roll 6, they will get an extra roll after moving the marker.
• The ladders should be used to go to a higher number only, and the snakes are used to go to a lower number. For the "interrupted" spaces (the squares being described by @Bass in his first comment below), both are immediately used (e.g. just as landing on 39 will bring you to 25, landing on 20 will bring you to 25 too).
• If someone lands on a square where there is already a player, it doesn't send him back to square 1.

Answer 1

The other guys already got the answer. (Maybe not with completely airtight arguments, but nevertheless.) The explanations would be a lot easier to follow if they had pictures, so here's one:

Legend:

• Red square: after turn 1, you are in one of these.
• Green square: after turn 2, you are in one of these, or in some red square (except square 2).
• Red circle with R: if Red was the last player to move, Red's turn started at one of these. (Because of the 4 visible as the last throw.)

From there, the solution is pretty simple:

1. Green has had either one or two turns.
2. Therefore, both Red and Blue have had at most three turns.
3. Therefore, because no green square overlaps with a letter R, Red was not the last to move.
3.1 There is no way to get to Red's current position within two turns, so Red has taken at least three turns. Combined with point 2, Red has taken exactly three turns.
3.2 Since Red has already taken three turns, but wasn't the last player to play, someone else must have also played three turns. It can only be Blue.
4. Because Red has played three turns, Green has taken 2 turns, rolling first 1, then 2.

So the only remaining things to check are that

5. Red really can get to its current square in 3 turns (yes, starting the third turn at 66, 62, 60 or 56.)
6. Blue can get to its current spot in 3 moves, ending with a 4 (yes, starting the third turn at 58, 60, 65, or indeed 77)

So finally, the answer is

It's Green's turn, and after that it's time for the fourth round, with Red playing next.

Answer 2

It is:

Green's Turn
The Turn order is: Red, Blue, Green

Reasoning:

Blue was the child who just rolled the 4, you know this because Green is only 3 spots from the beginning and if Red had rolled a 4 he would've started the last turn from an impossible position on top a chute
Because of Green's position he must have only taken 1 or 2 moves from the beginning of the game. Both Red and Blue's position is impossible to reach in 1 turn, as even with the roll again on 6 rule, they get trapped in an infinite loop with the slide from 31 to 7.
There are 9 effectively different starting positions for turn 2, a unique one for if their last roll landed them on one of the escape ladders or their last die roll. It is impossible to reach Red's current position or Blue's known starting position from any of these 9 starting positions, meaning that Red has already taken 3 turns, Blue has just taken his 3rd turn and Green must go next.

Answer 3

Assuming the order of players to roll the dice is R B G,
the next player after they come back from dinner will be

Green

Because

On the first round:
R rolled 6-6-6-6-5 => ends in 30.
B rolled 6-6-6-6-5 => ends in 30.
G rolled 1 => ends in 2.
On the second round:
R rolled 6-6-5 => ends in 66.
B rolled 6-6-3 => ends in 77.
G rolled 2 => ends in 4.
On the third round:
R rolled 6-6-6-6-6-3 => ends in 99.
B rolled 6-6-4 => ends in 77 again.
Last roll was 4 and now it is G's turn.