What a short word I am in this world
Only a few letters long
But many people still mistake me for my twin brother
We may sound the same, but trust me,
Our meanings are very different
Are you still confused? Then let me help you with a few hints
Add a letter to me and you can find my twin brother
Add 4 letters to me and I may have to wear an eyepatch
Now tell me, what am I?
3 Answers
You are:
Pi
What a short word I am in this world
Only a few letters long
Pi is only 2 letters long
But many people still mistake me for my twin brother
We may sound the same, but trust me,
Our meanings are very different
Pi is often confused with pie because they are homophones
Are you still confused? Then let me help you with a few hints
Add a letter to me and you can find my twin brother
Adding 'e' to pi gives us pie
Add 4 letters to me and I may have to wear an eyepatch
Adding 'rate' gives us pirate
Now tell me, what am I?
You are pi
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1$\begingroup$ To be honest, as soon as I read 'eye patch' I knew the answer had to be pirate. It's a great riddle though! :) $\endgroup$ Commented Aug 15, 2018 at 4:15
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$\begingroup$ Thanks. Will try to improve in future riddles :) $\endgroup$– Kevin LCommented Aug 19, 2018 at 13:16
You are
in
What a short word I am in this world. Only a few letters long
In is only 2 letters long
But many people still mistake me for my twin brother We may sound the same, but trust me, Our meanings are very different
In is often confused with inn because they are homophones
Are you still confused? Then let me help you with a few hints Add a letter to me and you can find my twin brother
Adding 'n' to in gives us inn
Add 4 letters to me and I may have to wear an eyepatch
Adding 'bl' and 'ds' gives us blinds
Now tell me, what am I?
You are in
Answer is PI. Adding another letter to it becomes PIE which sounds the same.
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1$\begingroup$ >! Adding an answer which has already has been provided could possible get you downvoted. Please check the previous answers before posting yours. Also, you should hide your answer in a spoiler. $\endgroup$ Commented Dec 5, 2018 at 8:01