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i) Which squares in the below game can you guarantee are mines?

ii) Which squares in the below game can you guarantee are not mines?

A proof is required that your answer is optimal.

Hint:

There is at least one unclicked square you can guarantee is a mine

enter image description here

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2 Answers 2

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There are four regions of unknown tiles. Call the three at the bottom A (size 5), B (size 2), C (size 2) from left to right, and the one at top right D.

Region C

contains exactly one mine. It can go in either square. Nothing we can see can possibly distinguish between the two possibilities.

Regions A and B

are close enough to interact. The possibilities for these regions are (case-splitting on what happens in region B): ! ! 4 ! 3 2 3 ! 3 . . ! 2 ! ! 1 . . 2 1 1 3 !
and ! ! 4 ! 3 2 3 ! 3 . . 2 ! ! 1 . . 2 1 1 3 !
where the latter can now be finished off by noting that the 4 needs two more mines adjacent to it: ! ! 4 ! 3 2 3 ! 3 ! ! 2 ! ! 1 ! 2 1 1 3 !
while the former possibility splits two ways: ! ! 4 ! 3 2 3 ! 3 ! ! 2 ! ! 1 ! 2 1 1 3 !
and ! ! 4 ! 3 2 3 ! 3 ! ! 2 ! ! 1 ! 2 1 1 3 !
All of these put 3 mines in region A and 1 in region B.

So now region D

must contain 7-(3+1+1) = 2 mines. The three squares at top right have to contain exactly one (because of the 4); the two at bottom have to contain exactly 1 (because of the 1); so the remaining two squares are clear. Now there is only one place to put the extra mine needed by the 3, namely to its southeast.

At this point we have the following unresolvable unknowns:

Regions A and B: the three possibilities above. Region C: the two possibilities above. Region D, top right: exactly one of those three cells has a mine in it.

To be more explicit about what is guaranteed:

the only guaranteed cells are in region D. In the 2x2 square at the bottom of that region, there is a mine in its southwest corner but not in any of the other three squares.

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  • $\begingroup$ Correct. One could also mention that one is guaranteed to find both mines in region D, but I did not ask this question. $\endgroup$
    – Improve
    Commented Apr 13, 2017 at 20:44
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Top right region is trivial to solve, you don't need to consider other regions (which are unsolvable).

2 below the 5 has 2 mines already. So tile under it is empty. So there is a mine below that empty tile. And given what numbers you receive afterwards, you will be certainly able to determine other mine's position.

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  • $\begingroup$ How did I miss that? Interesting that I had the same solution in mind as Gareth. $\endgroup$
    – Improve
    Commented Apr 14, 2017 at 10:26

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