I have a sequence of numbers - 1,3,5,7,9,11,13,15 I want to get the sum 30 by choosing 3 numbers from this sequence of numbers . The numbers can be repeated. Thank you
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5 Answers
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my choice is
11+13+3! = 11+13+6 =30
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As all these numbers are odd, the sum of three of them is odd as well. Is this a lateral-thinking puzzle? For example,
do some of the commas represent decimal points? 1.3+5.7=7, or with some similar trick we may achieve the sum of two being odd.
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$\begingroup$ ya it is kind of lateral thinking! $\endgroup$– gStephinCommented Jul 14, 2016 at 7:24
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There are many possible tweaks for this well known question
One of them Could be
11 + 3! + 13 = 30
or
()+15+15
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As adding three odd numbers would never give an even number...there must be a trick...
hence this is my best guess.
3!+9+15=30
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Also possible to do it these ways:
3*7 + 9
or
3*5 + 15
