The diagram is the outline of the surface of a 3D object. Several objects, like the one created from this given surface, may be used to create a cube.
Let me know if you need more clarifications to solve this one
The diagram is the outline of the surface of a 3D object. Several objects, like the one created from this given surface, may be used to create a cube.
Let me know if you need more clarifications to solve this one
I think we can do it with
3
copies of the given 3D object.
Note: I don't have a mathematical background, so this is mostly an intuitive "solve"and may not be very rigorous (or even correct). It also assumes that lengths that are visually equal, are (e.g. FD = EB = EJ
, FA = EA = AB = BC = CD = DA = BH = JH
).
Firstly fold the object on the red lines, like so:
Assuming (as stated above), edges FA = AB = AD
, etc, then the resulting polyhedron is
a skewed square-based pyramid, which fits neatly inside a cube of side length
FA
such that the baseABCD
is one face, and the pointE/F
is one of the top corners. Thus,FAD
andEBA
are both half faces of the cube, meaning we have two totally covered faces of the cube (so even intuitively we can see that three copies should cover all six faces).
If we call the remaining points of the cube, X
(above B
), Y
(above C
), and Z
(above D
), then we can
take another copy and place its base square on the
DCYZ
face and its apex atE
. This covers the second half of theAEZD
face and half the top (EXYZ
). Then we take a third copy and slide it in such that its vertex is again atE
, but with its base covering the whole of theXYCB
face. This covers the second half of theEXYZ
"top" and the second half of theEXBA
face.
Another way to think of this is to take the original object and
duplicate it three times, each time rotating through the diagonal
EC
axis, moving the base to a new face of the cube each rotation.
As I said at the top, I'm not sure how to approach a rigorous proof, but it's hopefully intuitive that
because all copies share the central
EC
axis and each internal face is at 45°, the copies can't be overlapping each other. Similarly, the large internal 45° triangles they must be completely face to face, meaning we can't be left with any gaps, so we've filled the cube entirely.