3
$\begingroup$

So my last math puzzle was too easy apparently, and this one might be too. Either way, the rules are the same.

  • No rotation.
  • No duplication.
  • No combination.
  • No rounding.
  • No computers.

Good luck to all of you!


You are given the following set of numbers: $1, 2, 3, 5, 6, 9$. Inject these numbers into the following equation to create a true statement.

$$\frac{21a + \frac{5b}{c}}{d} + e = f$$


Note

It was pointed out in the chat that I made a typo. I've corrected the number set; and I apologize to everyone for that mistake.

$\endgroup$
16
  • 2
    $\begingroup$ Oh boy, 720 possible combinations to choose from... Where to start..... $\endgroup$
    – Cubemaster
    Commented Sep 21, 2018 at 19:14
  • 2
    $\begingroup$ Is there a single solution? $\endgroup$ Commented Sep 21, 2018 at 19:16
  • 2
    $\begingroup$ There is only one solution. $\endgroup$ Commented Sep 21, 2018 at 19:19
  • 2
    $\begingroup$ You sure there is a solution to this? $\endgroup$
    – Robert S.
    Commented Sep 21, 2018 at 19:23
  • 2
    $\begingroup$ After trying to solve this, I gave up and made a Python script to try every possible combination. I haven't been able to find an answer that doesn't require rounding. I'll check again in case I made a mistake, but it's either that or this requires some lateral thinking. $\endgroup$
    – Racso
    Commented Sep 21, 2018 at 19:55

3 Answers 3

4
$\begingroup$

$$\frac{21a + \frac{5b}{c}}{d} + e = f$$ is true when

a = 2
b = 3
c = 5
d = 9
e = 1
f = 6

$\endgroup$
2
  • $\begingroup$ HAHA That was an awesome loop hole; however, it isn't the correct answer. I've updated the post as I made a typo. That should help lol $\endgroup$ Commented Sep 21, 2018 at 20:13
  • $\begingroup$ @Perp Changed now that the 4 is a 6 $\endgroup$ Commented Sep 21, 2018 at 20:14
2
$\begingroup$

Also not really an answer, but this is the closest I've gotten

$\frac{21*1 + \frac{5*4}{3}}{9} + 2 = 5\tfrac{2}{27}$ which is only off by $\frac{2}{27}$. So far that's the smallest margin of error that I could find. However rounding isn't allowed so...

EDIT: Actual answer:

$\frac{21*2 + \frac{5*3}{5}}{9} + 1 = 6$

$\endgroup$
5
  • $\begingroup$ The answer is similar to this. :) $\endgroup$ Commented Sep 21, 2018 at 19:48
  • $\begingroup$ @Perp Is mine correct? $\endgroup$ Commented Sep 21, 2018 at 20:05
  • $\begingroup$ Dang it! Too slow again! :P $\endgroup$ Commented Sep 21, 2018 at 20:22
  • 1
    $\begingroup$ d=9 is an overlap. also f=6 is kinda close to f = 5 and 2/27... $\endgroup$ Commented Sep 21, 2018 at 20:33
  • $\begingroup$ He found $d$ and $f$ was close but no rounding allowed. $\endgroup$ Commented Sep 21, 2018 at 20:34
1
$\begingroup$

Not an answer, but some facts I have found to help the community:

C != 4,9

$\endgroup$
1
  • $\begingroup$ That is a true statement. :) $\endgroup$ Commented Sep 21, 2018 at 19:47

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service and acknowledge you have read our privacy policy.

Not the answer you're looking for? Browse other questions tagged or ask your own question.