There seems to be a trend lately for simple math problems. So here is my version. It's super simple:
$23 + 62 = 94$
$41 + 22 = 36$
$10 + 20 = 21$
$50 + 17 = 22$
$67 + 96 = 172$
Problem:
$99 + 99 = x$
What is the value of $x$?
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asked Dec 15, 2017 at 16:59
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4$\begingroup$ it is 198. All your above additions are wrong. :P $\endgroup$– SidCommented Dec 15, 2017 at 17:07
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3 Answers
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The answer is
198
Explanation
23+62=94. // (6+3)(2+2)
41+22=36 // (2+1)(4+2)
67+96=172 //(9+7)(6+6) =16(12)
// carrying one gives us 172
Similarly
99+99=198
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Easiest way to look at this is
Reverse the first number then add to the second
I know this is the same as the other answers, but it explains the
99+99 case much better than (9+9)(9+9) which should be 1818.
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$\begingroup$ This also explains
50 +17better than the other answers. $\endgroup$– JasenCommented Dec 17, 2017 at 2:42
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The answer is:
198.
The reason is:
The first number is the sum of the second number and of the third one. The second number is the sum of the first number and of the last number.
For instance, for the first one, we have 23 + 62 = (3 + 6) and (2+2) = 94. In the case of 67+96=172, you had 67+96=(7+9)(6+6)=(16)(12). In such case, you summed the second number of the left member with the first member of the right one, giving here (16)(12) = (1)(6+1)(2) = 172.
So for the last one, we have 99 + 99 = (9+9)(9+9)=(18)(18)=(1)(8+1)(8)=198.
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$\begingroup$ I'm in a dilemma right now. Both you and @rudra answered the question at almost the same time. But rudra is 7 seconds faster so I think I'll accept his. Good job anyways! $\endgroup$ Commented Dec 15, 2017 at 17:23
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$\begingroup$ @ibrahimmahrir Ah ah. That's what I get for trying to put the reason earlier :p $\endgroup$– IzukaCommented Dec 15, 2017 at 17:24