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There seems to be a trend lately for simple math problems. So here is my version. It's super simple:

$23 + 62 = 94$
$41 + 22 = 36$
$10 + 20 = 21$
$50 + 17 = 22$
$67 + 96 = 172$

Problem:

$99 + 99 = x$

What is the value of $x$?

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  • 4
    $\begingroup$ it is 198. All your above additions are wrong. :P $\endgroup$ – Sid Dec 15 '17 at 17:07
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The answer is

198

Explanation

23+62=94. // (6+3)(2+2)
41+22=36 // (2+1)(4+2)
67+96=172 //(9+7)(6+6) =16(12)
// carrying one gives us 172

Similarly

99+99=198

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    $\begingroup$ when I did arithmetic (6+3)(2+2) = 36 not 94 $\endgroup$ – Jasen Dec 17 '17 at 2:40
  • $\begingroup$ also you have not explained 50+17 $\endgroup$ – Jasen Dec 17 '17 at 2:41
  • $\begingroup$ (0+1)(5+7)=1(12) carry one gives 22 $\endgroup$ – rudra Dec 17 '17 at 2:45
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Easiest way to look at this is

Reverse the first number then add to the second

I know this is the same as the other answers, but it explains the

99+99 case much better than (9+9)(9+9) which should be 1818.

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  • $\begingroup$ This also explains 50 +17 better than the other answers. $\endgroup$ – Jasen Dec 17 '17 at 2:42
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The answer is:

198.

The reason is:

The first number is the sum of the second number and of the third one. The second number is the sum of the first number and of the last number.
For instance, for the first one, we have 23 + 62 = (3 + 6) and (2+2) = 94. In the case of 67+96=172, you had 67+96=(7+9)(6+6)=(16)(12). In such case, you summed the second number of the left member with the first member of the right one, giving here (16)(12) = (1)(6+1)(2) = 172.
So for the last one, we have 99 + 99 = (9+9)(9+9)=(18)(18)=(1)(8+1)(8)=198.

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  • $\begingroup$ I'm in a dilemma right now. Both you and @rudra answered the question at almost the same time. But rudra is 7 seconds faster so I think I'll accept his. Good job anyways! $\endgroup$ – ibrahim mahrir Dec 15 '17 at 17:23
  • $\begingroup$ @ibrahimmahrir Ah ah. That's what I get for trying to put the reason earlier :p $\endgroup$ – Isuka Dec 15 '17 at 17:24

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