Here is where I am. Is there a unique solution somehow?
-
8$\begingroup$ You should indicate how many bombs remain to be found. $\endgroup$ – Jeff Zeitlin Jul 12 '18 at 16:51
-
$\begingroup$ Welcome to Puzzling.SE! $\endgroup$ – Chowzen Jul 12 '18 at 17:05
-
1$\begingroup$ I find that a lot of minesweeper games/apps make the game more "difficult" by forcing random guesses. Those are rather annoying as I think that these should be solvable with pure logic, zero guess work. $\endgroup$ – dcfyj Jul 12 '18 at 17:25
-
$\begingroup$ @dcfyj I am thinking the same way. It is meant to be a pure logic game, not a probabilistic one. $\endgroup$ – rfcoffee Jul 13 '18 at 17:47
With the information given,
there is no unique solution.
Both of the below are valid sets of mines (and there are two more, if you want to find them):![]()
-
1$\begingroup$ There may yet be a unique solution depending on how many mines there are; OP hasn't specified that yet. $\endgroup$ – F1Krazy Jul 12 '18 at 17:48
-
$\begingroup$ @F1Krazy True. There's only the one solution with 4 mines. It's not unique with any more than that. But that information wasn't given, so I haven't included it. $\endgroup$ – user27014 Jul 12 '18 at 18:07
Mnemonic has already answered your question; unfortunately there is no unique solution and you have to guess.
What I would like to point out is that your best option probability-wise is to click on one of the 10 edge squares not adjacent or diagonal to a number and work from there. The probability of a mine in those squares is between 1/10 and 1/5 whereas for the others it's between 1/3 and 2/3.
-
1
-
2$\begingroup$ I counted 93 bombs found out of the 99 bombs on expert mode meaning 6 left. $\endgroup$ – SadioFirmiMo Jul 12 '18 at 17:56