5
$\begingroup$

If  $$\begin{align}2*6&=7,\\4*2&=72\quad\text{and}\\7*3&=144\end{align}$$

then,

$$\;\;5*8=\;?\qquad\qquad$$

$\endgroup$
  • $\begingroup$ Is it relevant that 144 vf n ahzore va gur Svobanppv frdhrapr. $\endgroup$ – jsm May 3 '18 at 15:35
  • 3
    $\begingroup$ the others aren't so why would it matter if 144 is? Just curious about your thinking... $\endgroup$ – Dr t May 3 '18 at 16:09
  • $\begingroup$ what exactly...did @Mike Earnest just edit here that lends clarity and meaning to the initial post? I didn't see any change. Please explain. $\endgroup$ – Dr t May 3 '18 at 16:33
  • $\begingroup$ @Drt I removed the [logical-deduction] tag and replaced it with [pattern], since this puzzle cannot be solved by logical inference alone. $\endgroup$ – Mike Earnest May 3 '18 at 16:37
  • 6
    $\begingroup$ Your multiplication is wrong. $\endgroup$ – Rajan May 5 '18 at 11:58
3
$\begingroup$

Not sure about any mathematic operation but can find this pattern(could be wrong!):

$2∗6 = 7$;
$4∗2 = 72$; 7 from RHS of 1st row and 2 1st number in 1st row.
$7∗3 = 144$; 7*2 from RHS of 2nd row(multiply) and 4 1st number in 2nd row.

So,

$5∗8 = 167$; $1*4*4$ from RHS of 3rd row and 7 1st number in 3rd row.

edit: just noticed i mistaken 7 with 17, so corrected;)

$\endgroup$
1
$\begingroup$

I found the same pattern as @Preet, but had a different result:

$2 * 6 = 7 \Rightarrow 7 $; initial statement
$4 * 2 = 72 \Rightarrow 7$ ~ $2 $; product of previous result (just 7) & first row (2)
$7 * 3 = 144 \Rightarrow 14$ ~ $4 $; product of previous result $(7*2 = 14)$ and first row (4)
$5 * 8 = 567 \Rightarrow 56$ ~ $7 $; product of previous result $(14*4 = 56)$ and first row (7)

So the answer might be

$567.$

$\endgroup$
-6
$\begingroup$

Strip out the symbols and multiply by 16 to find the next row

2*6=7 => 267 * 16 = 4272
4*2=72 => 4272 * 16 = 73144
7*3=144 => 73144 * 16 = 581704
therefore: 5*8=1704

$\endgroup$
  • 4
    $\begingroup$ $4272\cdot16=68352$ and $73144\cdot16=1170304$? Or just note that the products of the units digits don't even match? Or that $581703$ is odd? $\endgroup$ – noedne May 4 '18 at 19:35
  • $\begingroup$ edited to correct $\endgroup$ – omikes May 4 '18 at 19:52
  • 4
    $\begingroup$ How are you obtaining these numbers? $\endgroup$ – noedne May 4 '18 at 19:56
  • 6
    $\begingroup$ Yes, I agree with @noedne, the second and third products aren't correct. $\endgroup$ – hexomino May 4 '18 at 20:06

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Not the answer you're looking for? Browse other questions tagged or ask your own question.