COLOR-PUZZLE. Complete the picture

Question

Here is a color-puzzle(Not the best picture but hey :D) If anything is unclear, let me know. But all the information you need should be out there. So... Try complete the picture.

Hint1:

It's not {2(1),3,4,6}

Answer 1

I would color it like this

The circle is divided into 12 30° sectors.
The red rectangle contains a regular hexagon, each of whose angles is 120° so it takes up 4 sectors. The yellow rectangle contains a square, each of whose angles is 90° or 3 sectors. The grey rectangle contains an equilateral triangle, each of whose angles is 60° or 2 sectors. The blue rectangle contains what appears to be a 30° angle which takes up one sector. The two hatched sectors are unused.

Answer 2

I believe this to be the answer to your question...(I may be wrong though)

Here, is my explanation:

every colour embedded with the rectangle box have vertices:-

• (R)red triangle 3
• (G)grey hexagon 6
• (B)blue square 4
• (Y)yellow converging lines 1

Every vertices is sum of the vertices to which is diagonal and vertices that is vertically opposite to it, minus the vertices that horizontally opposite to it :-


B=(Y+G)- R = (6 + 1) - 3 = 4
R=(Y+G)- B = (6 + 1) - 4 = 3
Y=(R+B)-G =  (4 + 3) - 6 = 1
G=(R+B)-Y =  (4 + 3) - 1 = 6

[from the placements of rectangle this shows which are vertically opposite, horizontally opposite and diagonal

+--------------------------------------------------------------------------+
| shape-vertices = vertically opposite + diagonally-opp - horizontally-opp |
+--------------------------------------------------------------------------+
| red-tri(R)       grey-hexa(G)          yellow-lines(Y)  Blue-rect(B)     |
| grey-hexa(G)     red-tri(R)            blue-rect(B)     yellow-ines(Y)   |
| yellow-lines(Y)  red-tri(R)            Blue-rect(B)     grey-hexa(G)     |
| blue-rect(B)     grey-hexa(G)          yellow-lines(Y)  red-tri(R)       |
+--------------------------------------------------------------------------+

you may be thinking that how does all of this give you the colours(please bear with me a little :P)

Now the circle has twelve sectors...

the relation between these sectors can be determined with same formula from above. Red(R) Blue(B) Grey(G) Yellow(Y).

B=(Y+G)- R = (8 + 10) - 6 = 12
R=(Y+G)- B = (8 + 10) - 12 = 6
Y=(R+B)-G =  (6 + 12) - 10 = 8
G=(R+B)-Y =  (6 + 12) - 8 = 10

however we can determine the next occurrence of the colour in the sector by subtracting from 12.The next sector with the colour:-

• Blue will be 0 (12-12)
• Red will be 6 (12-6)
• Grey will be 2 (12-10)
• Yellow will be 4(12-8)

Answer 3

+-------------------+---------+-------+
|      Colour       | letters | sides |
+-------------------+---------+-------+
| blue              |       4 |     4 |
| gold              |       4 |     2 |
| grey              |       4 |     6 |
| red               |       3 |     3 |
+-------------------+---------+-------+

Here,

I add a number of edges of each shape with the number of letters in the colour's name, and then divide it by 2. For example, if I want to know how many sectors away from red grey occurs, I add $(6+4)/2 = 5$.

From the rounded rectangles you can determine which colour follows which colour. For example, grey follows red, blue follows gold (and vice-versa).

So, I think this could be the answer:

Red $= (6+4)/2 = 5$, so red must be 5 sectors away from grey. Similarly, gold $= (4+4)/2 = 4$, so gold must be 4 sectors away from blue. As such, my solution is