Find this Unique UVC Palindrome ( ignoring signs and decimal) from Given Fractional Relationship

Question

Given:

U, V, C are three distinct digits ( 0 to 9 ).

UVVVV and CVVVV.U are concatenated numbers.

Dot “.” Stands for decimal.

Relation:

$UVVVV/C= CVVVV.U$

Find U, V , C

Answer 1

Finding $C$

1. If dividing an integer by $C$ gives a fraction with exactly one digit after the decimal point (note that $U=0$ doesn't work), then $C$ must be non-coprime with $10$, i.e. it must be one of $2,4,5,6,8$.

2. If $C\geq45$, then the right-hand side is more than $40,000$, and after multiplying by $C$ it won't be a 5-digit number any more. So we must have $C=2$.

Finding $U$ and $V$

1. Since $C=2$, the division by $C$ must give $U=5$.

2. Since $UVVVV$ divided by $2$ is not an integer, $V$ must be odd. Trying the possibilities in turn shows that $V=9$ is the only one which works.

Summary

$U=5,V=9,C=2$. The equation is $59999/2=29999.5$.

Answer 2

$59999/2=29999.5$

because:

$C=1,2,3$ due to RHS being $\sim C^2$ in magnitude, which must be five digits. $C=1$ means $U=0$ which is impossible, and $C=3$ means $(C\times .U) \pmod 1 \equiv 0$ which is also impossible. Therefore $C=2, U=5$.

and then:

We now have$\frac{5VVVV}{2}=2VVVV.5$ which leads to $5000+\frac{VVVV}{2}=VVVV.5$ by cancelling $20,000$ from each side. So $10000+VVVV=2VVVV+1$ and then $VVVV=9999$, so $V=9$.

Answer 3

Ok so others have got there before me, but I have a slightly different way of approaching I think...

C cannot be 1,3,7,9,0 because.. 1 would not give a decimal point, 3 7 9 would give more than one decimal point or no decimal points e.g. 2/3 = 0.66666etc., and we cannot conveniently divide by 0 - thus C must be 2,4,5,6,8

now

C = U/C more or less because when the divide the first digit, U, by C we need to get C in the first column... Now for C=2 we could have U=4, but we can't have .4 at the end of the answer we need .5 so U must be 5 if C=2 - this works because 5VVVV/2 = 2VVVV.5 is possible if V is odd... but if we try C=4,5,6,8 we cannot find a single digit that will fit e.g. 8VVVV/4 = 2VVVV... and we need 4 at the front... thus for C>2 we cannot get the first digit to work - thus C=2 and U=5 (unless, of course, C=3 and U=9, but then we would not get the single digit after the decimal point at the end of number... )

finally

By inspection V=9 works if C=2 and U=5 and V=1,3,5,7 do not work (of course even V does not give .5 at the end) so we have $$59999/2=29999.5$$

and

this works for any number of 9s in the middle... 5/2 = 2.5; 59/2 = 29.5;....; 59999999999/2 = 29999999999.5 etc.