$P$, $Q$, $R$ are three distinct Prime Numbers
$P!$ = $Q$ x $R^Q$ x $P$
Find P, Q, R.
Puzzling Stack Exchange is a question and answer site for those who create, solve, and study puzzles. It only takes a minute to sign up.Sign up to join this community
I think it’s
P = 5, Q = 3, and R = 2.
$5! = 120 = 3 \times 2^3 \times 5$.
We note that
$P! = P \times (P-1)!$, so $(P-1)! = R^Q \times Q$. Noting that one of P, Q, and R had to be at least 5, I noted that $4 = 2^2$ and so $4 \times 2 = 2^3$ was probably a convenient way to include these factors of $P!$.