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broke up run-on sentences, [rebus] suggests a solving method
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This is a rebus puzzle describing a singer's name, this. This puzzle will still be pretty straight-forward, though you really need a little knowledge in programming this time...

import math

a = name['>_']
b = name['&']
c = name[(-1)**.5]
d = name[sum(1 / math.factorial(i) for i in range(20))]
e = name['8848m']
f = name['android']
assert [len(i) for i in (a, b, c, d, e, f)] == [7, 3, 1, 1, 16, 5]
answer = '{}{}{}{}\x20{}{}'.format(a[::3], b[1], c, d, e.split()[0].replace('lest', ''), f[2::])

The answer is the hypothetical value of the variable answer of the Python program above.

But you don't have to run the code at all, in. Un fact you can't run it, the. The first line will raise NameError, because name is not defined, and that. That is the whole point of this puzzle,: you need to guess what the name dictionary contains, its. Its values are all strs,. I updated the code so you can actually get the keys, the. The values are simple English words/phrases that are related to the keys in a natural way, the. The clues are all there in the "code", and did. Did you notice the knowledge tag?

This is a rebus puzzle describing a singer's name, this puzzle will still be pretty straight-forward, though you really need a little knowledge in programming this time...

import math

a = name['>_']
b = name['&']
c = name[(-1)**.5]
d = name[sum(1 / math.factorial(i) for i in range(20))]
e = name['8848m']
f = name['android']
assert [len(i) for i in (a, b, c, d, e, f)] == [7, 3, 1, 1, 16, 5]
answer = '{}{}{}{}\x20{}{}'.format(a[::3], b[1], c, d, e.split()[0].replace('lest', ''), f[2::])

The answer is the hypothetical value of the variable answer of the Python program above.

But you don't have to run the code at all, in fact you can't run it, the first line will raise NameError, because name is not defined, and that is the whole point of this puzzle, you need to guess what the name dictionary contains, its values are all strs, I updated the code so you can actually get the keys, the values are simple English words/phrases that are related to the keys in a natural way, the clues are all there in the "code", and did you notice the knowledge tag?

This is a rebus puzzle describing a singer's name. This puzzle will still be pretty straight-forward, though you really need a little knowledge in programming this time...

import math

a = name['>_']
b = name['&']
c = name[(-1)**.5]
d = name[sum(1 / math.factorial(i) for i in range(20))]
e = name['8848m']
f = name['android']
assert [len(i) for i in (a, b, c, d, e, f)] == [7, 3, 1, 1, 16, 5]
answer = '{}{}{}{}\x20{}{}'.format(a[::3], b[1], c, d, e.split()[0].replace('lest', ''), f[2::])

The answer is the hypothetical value of the variable answer of the Python program above.

But you don't have to run the code at all. Un fact you can't run it. The first line will raise NameError, because name is not defined. That is the whole point of this puzzle: you need to guess what the name dictionary contains. Its values are all strs. I updated the code so you can actually get the keys. The values are simple English words/phrases that are related to the keys in a natural way. The clues are all there in the "code". Did you notice the tag?

added 64 characters in body; edited tags
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This is a rebus puzzle describing a singer's name, this puzzle will still be pretty straight-forward, though you really need a little knowledge in programming this time...

import math

a = name('>_')name['>_']
b = name('&')name['&']
c = name(name[(-1)**.5)5]
infd = floatname[sum('inf')
d1 =/ name(math.factorial(1i) +for 1/infi in range(20)**inf)]
e = name('8848m')name['8848m']
f = name('android')name['android']
assert [len(i) for i in (a, b, c, d, e, f)] == [7, 3, 1, 1, 16, 5]
answer = '{}{}{}{}\x20{}{}'.format(a[::3], b[1], c, d, e.split()[0].replace('lest', ''), f[2::])

The answer is the hypothetical value of the variable answer of the Python program above, that is, if you have a computer that can actually deal with infinity...

But you don't have to run the code at all, in fact you can't run it, the first line will raise NameError, because name function is not defined, and that is the whole point of this puzzle, you need to guess what the name function doesdictionary contains, based on its expected outputs.

And once you figured that outvalues are all strs, the rest ofI updated the puzzle will be extremely easy (ifcode so you understand Pythoncan actually get the keys, the values are simple English words/phrases that is...).

The answer isare related to the name ofkeys in a certain female singer...natural way, the clues are all there in the "code", and did you notice the knowledge tag?

This is a rebus puzzle describing a singer's name, this puzzle will still be pretty straight-forward, though you really need a little knowledge in programming this time...

a = name('>_')
b = name('&')
c = name((-1)**.5)
inf = float('inf')
d = name((1 + 1/inf)**inf)
e = name('8848m')
f = name('android')
assert [len(i) for i in (a, b, c, d, e, f)] == [7, 3, 1, 1, 16, 5]
answer = '{}{}{}{}\x20{}{}'.format(a[::3], b[1], c, d, e.split()[0].replace('lest', ''), f[2::])

The answer is the hypothetical value of the variable answer of the Python program above, that is, if you have a computer that can actually deal with infinity...

But you don't have to run the code at all, in fact you can't run it, the first line will raise NameError, because name function is not defined, and that is the whole point of this puzzle, you need to guess what the name function does, based on its expected outputs.

And once you figured that out, the rest of the puzzle will be extremely easy (if you understand Python, that is...).

The answer is the name of a certain female singer...

This is a rebus puzzle describing a singer's name, this puzzle will still be pretty straight-forward, though you really need a little knowledge in programming this time...

import math

a = name['>_']
b = name['&']
c = name[(-1)**.5]
d = name[sum(1 / math.factorial(i) for i in range(20))]
e = name['8848m']
f = name['android']
assert [len(i) for i in (a, b, c, d, e, f)] == [7, 3, 1, 1, 16, 5]
answer = '{}{}{}{}\x20{}{}'.format(a[::3], b[1], c, d, e.split()[0].replace('lest', ''), f[2::])

The answer is the hypothetical value of the variable answer of the Python program above.

But you don't have to run the code at all, in fact you can't run it, the first line will raise NameError, because name is not defined, and that is the whole point of this puzzle, you need to guess what the name dictionary contains, its values are all strs, I updated the code so you can actually get the keys, the values are simple English words/phrases that are related to the keys in a natural way, the clues are all there in the "code", and did you notice the knowledge tag?

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A rebus puzzle describing a name

This is a rebus puzzle describing a singer's name, this puzzle will still be pretty straight-forward, though you really need a little knowledge in programming this time...

a = name('>_')
b = name('&')
c = name((-1)**.5)
inf = float('inf')
d = name((1 + 1/inf)**inf)
e = name('8848m')
f = name('android')
assert [len(i) for i in (a, b, c, d, e, f)] == [7, 3, 1, 1, 16, 5]
answer = '{}{}{}{}\x20{}{}'.format(a[::3], b[1], c, d, e.split()[0].replace('lest', ''), f[2::])

The answer is the hypothetical value of the variable answer of the Python program above, that is, if you have a computer that can actually deal with infinity...

But you don't have to run the code at all, in fact you can't run it, the first line will raise NameError, because name function is not defined, and that is the whole point of this puzzle, you need to guess what the name function does, based on its expected outputs.

And once you figured that out, the rest of the puzzle will be extremely easy (if you understand Python, that is...).

The answer is the name of a certain female singer...