Search Results
| Search type | Search syntax |
|---|---|
| Tags | [tag] |
| Exact | "words here" |
| Author |
user:1234 user:me (yours) |
| Score |
score:3 (3+) score:0 (none) |
| Answers |
answers:3 (3+) answers:0 (none) isaccepted:yes hasaccepted:no inquestion:1234 |
| Views | views:250 |
| Code | code:"if (foo != bar)" |
| Sections |
title:apples body:"apples oranges" |
| URL | url:"*.example.com" |
| Saves | in:saves |
| Status |
closed:yes duplicate:no migrated:no wiki:no |
| Types |
is:question is:answer |
| Exclude |
-[tag] -apples |
| For more details on advanced search visit our help page | |
Results tagged with mathematics
Search options not deleted
user 10510
A puzzle related to mathematical facts and objects, whose solution needs mathematical arguments. General mathematics questions are off-topic but can be asked on Mathematics Stack Exchange.
15
votes
x⌊x⌊x⌊x⌋⌋⌋ = 2020
Let us denote
$$\aleph(x)=x\lfloor x\lfloor x\lfloor x\rfloor\rfloor\rfloor\,.$$Since the fourth root of $2020$, $\sqrt[4\,]{2020}$, is located between 6 and 7, the solution $x^\star$ is either $x^\s …
- 249