This is in the spirit of the What is a Word/Phrase™ series started by JLee with a special brand of Phrase™ and Word™ puzzles.

If a word conforms to a special rule, I call it a Trio Word™.
Use the following examples below to find the rule.

$$ % set Title text. (spaces around the text ARE important; do not remove.) % increase Pad value only if your entries are longer than the title bar. % \def\Pad{\P{2.0}} \def\Title{\textbf{ Trio }} % \def\S#1#2{\Space{#1}{20px}{#2px}}\def\P#1{\V{#1em}}\def\V#1{\S{#1}{9}} \def\T{\Title\textbf{Words}^{\;\!™}\Pad}\def\NT{\Pad\textbf{Not}\T\ }\displaystyle \smash{\lower{29px}\bbox[yellow]{\phantom{\rlap{rubio.2019.05.15}\S{6px}{0} \begin{array}{cc}\Pad\T&\NT\\\end{array}}}}\atop\def\V#1{\S{#1}{5}} \begin{array}{|c|c|}\hline\Pad\T&\NT\\\hline % \text{ BANANA }&\text{ APPLE }\\ \hline \text{ EAST** }&\text{ WEST }\\ \hline \text{ NORTH }&\text{ SOUTH }\\ \hline \text{ UNFORTUNATELY }&\text{ FORTUNATELY }\\ \hline \text{ PLAY }&\text{ READ }\\ \hline \text{ PLAYING }&\text{ READING }\\ \hline \text{ DOGS** }&\text{ DOG }\\ \hline \text{ CAT }&\text{ CATS }\\ \hline \text{ DOOMSDAY }&\text{ ARMAGEDDON }\\ \hline \text{ THOUSAND }&\text{ HUNDRED }\\ \hline \text{ PAINTING** }&\text{ DRAWING }\\ \hline \end{array}$$

For Trio Word™ marked star above, it's also the Perfect Trio Word™, please also specify what condition makes the perfection. :P

And, if you want to analyze, here is a CSV version:

Trio Words™,Not Trio Words™

Hint 1:

https://www.calculator.net/big-number-calculator.html -> For verification

Hint 2:


  • 2
    $\begingroup$ shouldn't play be perfect as well? $\endgroup$ – Omega Krypton Jul 31 at 10:37
  • $\begingroup$ Yes, PLAY is Trio but not perfect. $\endgroup$ – Conifers Jul 31 at 10:41
  • $\begingroup$ Added one more example PAINTING as a Perfect Trio Word~ $\endgroup$ – Conifers Jul 31 at 12:31
  • $\begingroup$ hey there, any hints? $\endgroup$ – Omega Krypton Aug 17 at 5:24
  • $\begingroup$ @OmegaKrypton Just really close to the Perfect Trio Word... in comments need a little adjustment to get it :) $\endgroup$ – Conifers Aug 18 at 14:02

A Trio word:

has its value divisible by 3 when decrypted with A1Z26

A Not-Trio word:

has its value indivisible by 3 when decrypted with A1Z26

A Perfect Trio Word:

has its value equal to 45 or 90 when decrypted with A1Z26. only from the examples, it may not be able to determine the most suitable criteria for such category. @Bananenkopp proposed a very propable case that Perfect Trio Words have their value being a Triangular Number. @Hugh also proposed a possible solution that their values are divisible by 9. Another possible case is that their values are divisible by 5/15/45.

  • 2
    $\begingroup$ UNSTABLE is 21+14+19+20+1+2+12+5 = 94 = not value divisible by 3. I was about to post my answer, but found that. $\endgroup$ – Jan Ivan Jul 31 at 10:07
  • 1
    $\begingroup$ @Jan Ivan I have changed an example pair :P $\endgroup$ – Conifers Jul 31 at 10:29
  • 2
    $\begingroup$ maybe the reason for perfection is its value is a rot13(Gevnathyne ahzore) $\endgroup$ – Bananenkopp Jul 31 at 11:25
  • 1
    $\begingroup$ Not close to the rot13(Gevnathyne ahzore) :P $\endgroup$ – Conifers Jul 31 at 12:54

Just a small expansion of OmegaKrypton answer:

A Perfect Trio Word:

is where the number obtained by A1Z26 is divisible by 9 (it's my first answer), but as noticed in comments then play also should be perfect word while it's not, so we can add another divisor. For the perfect words we see their decomposition as
$1) 3*3*5$
$2) 3*3*5$
$3) 2*3*3*5$
We can conclude that common prime factors are 3*3*5, so perfect word is word which A1Z26 cipher sum divisible by 3*3*5=45

  • $\begingroup$ not necessarily... $\endgroup$ – Omega Krypton Jul 31 at 10:53
  • 3
    $\begingroup$ play = 54 but not perfect $\endgroup$ – Omega Krypton Jul 31 at 11:00
  • $\begingroup$ Nice attempt, need be more perfect :P $\endgroup$ – Conifers Jul 31 at 13:22
  • $\begingroup$ Just one step closer to the perfection~ $\endgroup$ – Conifers Aug 5 at 3:36
  • 2
    $\begingroup$ This seems arbitrary. Okay, how about that a perfect trio word is divisible by 3*3*(((33/3) mod 3)+3)? $\endgroup$ – hdsdv Aug 5 at 9:56

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