Can you fill this grid ? Version ($\pi$)
In text:
?14516 243748 120581 17186? 01?857
HINT 1
It's a big spiral!!!
HINT 2
It starts from 0 at the center!
HINT 3
Colors included to identify
$\begingroup$
$\endgroup$
5
-
4$\begingroup$ Wait, are you declaring π = 3.0 now? Indiana, is that you? $\endgroup$– Rubio ♦Commented May 6, 2019 at 17:50
-
$\begingroup$ 3rd partial sum in some $\pi$ approximation? $\endgroup$– z100Commented May 6, 2019 at 18:58
-
$\begingroup$ No, 3.0 stands for my 3rd puzzle and $\pi$ is the clue. $\endgroup$– 19akshCommented May 7, 2019 at 1:33
-
$\begingroup$ Rubio LOL!( I love this site!) $\endgroup$– George MenoutisCommented May 7, 2019 at 7:11
-
$\begingroup$ @PiIsNot3 ... Rubio's comment... $\endgroup$– Omega KryptonCommented May 7, 2019 at 16:41
Add a comment
|
1 Answer
$\begingroup$
$\endgroup$
2
The final grid is
014516 243748 120581 171869 010857
And the pattern is
A clockwise spiral out from the center of the following function, displayed such that each digit of a multidigit number occupies one grid square
f(1)=0, f(n+1)=f(n)+O(n+(-1)^n) where O(n) is the nth odd number, or 2n-1
example: f(2) = f(1)+O(3) = 0+5 = 5, F(3) = f(2)+O(2) = 5+3 = 8...
answered May 7, 2019 at 16:10
-
1$\begingroup$ One member deleted a comment using more intuitive solution, based on sequence of "almost squares" $0,5,8,17,24,37,48,65,80,101,120,145,168,197$ which represents $f(n)=n^2-(-1)^n$. Of course your solution is totaly equivalent, so upvoted it. $\endgroup$– z100Commented May 7, 2019 at 19:55
-
1$\begingroup$ I must be missing something obvious here - but how does this link with 𝜋 being the clue? $\endgroup$ Commented May 7, 2019 at 21:18