7
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Can you fill this grid ? Version ($\pi$)
enter image description here

In text:

?14516
243748
120581
17186?
01?857

HINT 1

It's a big spiral!!!

HINT 2

It starts from 0 at the center!

HINT 3

Colors included to identify

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5
  • 4
    $\begingroup$ Wait, are you declaring π = 3.0 now? Indiana, is that you? $\endgroup$
    – Rubio
    May 6, 2019 at 17:50
  • $\begingroup$ 3rd partial sum in some $\pi$ approximation? $\endgroup$
    – z100
    May 6, 2019 at 18:58
  • $\begingroup$ No, 3.0 stands for my 3rd puzzle and $\pi$ is the clue. $\endgroup$
    – 19aksh
    May 7, 2019 at 1:33
  • $\begingroup$ Rubio LOL!( I love this site!) $\endgroup$ May 7, 2019 at 7:11
  • $\begingroup$ @PiIsNot3 ... Rubio's comment... $\endgroup$ May 7, 2019 at 16:41

1 Answer 1

3
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The final grid is

014516
243748
120581
171869
010857

And the pattern is

A clockwise spiral out from the center of the following function, displayed such that each digit of a multidigit number occupies one grid square
f(1)=0, f(n+1)=f(n)+O(n+(-1)^n) where O(n) is the nth odd number, or 2n-1
example: f(2) = f(1)+O(3) = 0+5 = 5, F(3) = f(2)+O(2) = 5+3 = 8...

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2
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    $\begingroup$ One member deleted a comment using more intuitive solution, based on sequence of "almost squares" $0,5,8,17,24,37,48,65,80,101,120,145,168,197$ which represents $f(n)=n^2-(-1)^n$. Of course your solution is totaly equivalent, so upvoted it. $\endgroup$
    – z100
    May 7, 2019 at 19:55
  • 1
    $\begingroup$ I must be missing something obvious here - but how does this link with 𝜋 being the clue? $\endgroup$ May 7, 2019 at 21:18

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