Finally, someone has figured it out. Good job.
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1$\begingroup$ Observation: so far there's only one A in the entire grid. Four C's, five B's, five D's. $\endgroup$– Rand al'ThorCommented Apr 2, 2019 at 15:32
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$\begingroup$ It kind of looks like the choices are not right...the answer I come up with is close to #3 but not exactly... $\endgroup$– Dr tCommented Apr 2, 2019 at 19:57
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1$\begingroup$ I see the Illuminati on the 3rd square in the first row. The triangle with the circle eye in it! Maybe its a clue! $\endgroup$– xilpexCommented Apr 2, 2019 at 23:25
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1$\begingroup$ Observation: the 15 in the grid do not have any duplicates, however, picking one of the four answers will create a duplicate $\endgroup$– MetaZenCommented Apr 4, 2019 at 18:10
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3$\begingroup$ @RudyMatunic You may want to drop a hint before your bounty expires. It seems the community hasn't been able to make progress on this despite pretty decent visibility. $\endgroup$– Rubio ♦Commented Apr 10, 2019 at 22:05
12 Answers
I believe the answer is
1
Reasoning:
I replaced letters with numbers (A=1, B=2, C=3 and D=4) as well edges in shapes with numbers (circle = 0, line = 1, triangle = 3 and square = 4). The sum of letters and the sum of the edges matches in each row. For example the first row: B+D+B+D=2+4+2+4=12 Square+Line+Triangle+Square=4+1+3+4=12 EDIT: It's also true for columns.
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2$\begingroup$ Holy crap, this makes sense! Please elaborate and add additional context to this answer; i.e. show examples! Because this answer might just be it! Also, welcome to the Puzzling Stack Exchange (PSE)! Since you are a new contributor, and in fact new to the Stack Exchange, I strongly advise that you visit the Help Center and/or take the tour if you have not already. Otherwise, happy puzzling, my friend! I hope for more answers to come from you in the future, but most of all, hope you enjoy! :D $\endgroup$– Mr PieCommented Apr 14, 2019 at 15:39
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$\begingroup$ Yes, I believe this answer is correct. Well done. $\endgroup$– jsmCommented Apr 14, 2019 at 16:30
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$\begingroup$ This looks like the right answer. Good job $\endgroup$– ArtemmmCommented Apr 16, 2019 at 2:26
In each row, number of distinct shapes (each figure has one shape) + number of distinct letters = 6. Only option 3 will fulfill this pattern on row 3.
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$\begingroup$ I think you've miscounted, or didn't express yourself fully. Using your method to count I don't get the same for each row. $\endgroup$– AmorydaiCommented Apr 5, 2019 at 15:10
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Is it:
3
because:
A has 1 circle, B has 2 and D has 4, so C must have 3.
Ok, this is my second attempt! The answer is:
option 3!
explanation:
Consider giving each letter and shape a value like this: A=4, B=3, C=2, D=1, Rectangle=Circle=2 and Triangle=Line=anything!
Then :
if we add the values in each row, we get these numbers: First row=18+Line+Triangle=18+2*Line/Triangle.- Second row=18+2*Lines=18+2*Line/Triangle.- Fourth row=18+2*Lines=18+2*Line/Triangle.
Therefore:
considering the third row has the same value, it should also be like 18+2*Line/Triangle. So far, it is 14+1*Triangle, so the only option that can make it 18+2*Line/Triangle, is option 3.
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$\begingroup$ But why organise the values in the way you have done for the rectangle and circle, and the triangle and line? This answer looks like a bit of coincidence, and I would thus be surprised if it was the real answer, albeit it is pretty cool nonetheless ;) $\endgroup$– Mr PieCommented Apr 13, 2019 at 13:52
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$\begingroup$ What do you mean by "coincidence"?! This problem is already weird and I'm not saying that I got those values through logical steps! I just guessed that rows should have equal values (Actually I have had like a billion guesses since I saw this problem!) and I tried to find values that fit! $\endgroup$ Commented Apr 13, 2019 at 14:50
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$\begingroup$ I am saying it might be a coincidence because you let rectangle=circle=2 (why?) and triangle=line=anything (again, why?). Look, perhaps to say it is a "coincidence" is a bit harsh and disrespects your efforts, so I won't say that from now; but what I will say is that your decision to let the shapes equal those certain values seems arbitrary, no? $\endgroup$– Mr PieCommented Apr 14, 2019 at 10:15
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1$\begingroup$ Yes it is! As I said, I just tried to find values that could fit my whole "equal value in each row" concept! And even though recent answers by other people are more beautiful and (in my opinion) correct, I believe I deserve some reputation because of starting the whole equal row stuff! Also, even my answer is ugly, it is still logically correct! I believe this problem has multiple answers, some beautiful some ugly(also look at my first attempt. That one is also correct but ugly!). Do you agree? $\endgroup$ Commented Apr 14, 2019 at 19:47
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I believe the answer is:
3 (a.k.a: C or option number 3)
My reasoning:
I believe that the crosses and circle, and all that are just trying to fool you. So if you take those out, and put the normal numbers assigned to each letter (D is to 1, B is to 2, etc.), you will see a pattern going horizontally:
First row: 2, 1, 2, 1
Second row: 1, 2, 3, 4
Third row: 2, 2, ?(3), 3
Fourth row: 3, 3, 1, 1
Here you can see and obvious pattern. Then for the question mark, the pattern comes in duos: Two 2s, and Three 3s. That means the missing number is 3, and since the C is 3, the missing square is the C one.
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5$\begingroup$ The shapes have something to do with the puzzle $\endgroup$ Commented Apr 3, 2019 at 1:24
I think the answer is
number 1.
Because
When we look diagonally, option 1 is the most logical one.
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3$\begingroup$ How is it most logical? Is it because there are two B's and so there must be two D's, irrespective of the circles lines and squares? $\endgroup$– Mr PieCommented Apr 14, 2019 at 11:34
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$\begingroup$ Not just that. There is a pattern in letters diagonally from left to right, and a pattern in shapes diagonally from right to left. Also, looking diagonally from top right, just one symbol is crossed. $\endgroup$– AntonijaCommented Apr 15, 2019 at 13:04
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1$\begingroup$ So, my answer was the first correct one. Regardless the explanation. $\endgroup$– AntonijaCommented May 14, 2019 at 9:57
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$\begingroup$ Hmm... you do have a point, there... $(+1)$ $\endgroup$– Mr PieCommented May 14, 2019 at 12:37
This might be a heck of a stretch..
If you count each unique symbol as a note on sheet music and use the slashes to determine sharp/flat, and then you use the letters to determine length of the note (quarter, half, whole, etc.) it creates _____ some unrecognizable music as far as I can tell. However, the only one that would fit with 4/4 music is :
selection 4, (A).
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$\begingroup$ Although this was posted as an answer, it does not appear to attempt answering the question; it should possibly be a comment or even deleted altogether, thus I have in consequence flagged this as not an answer. Hope you understand. $\endgroup$– Mr PieCommented Apr 13, 2019 at 13:55
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5$\begingroup$ ... but it does attempt to answer the question. I agree it's a "heck of a stretch" but it's an answer justified with a reasoning. $\endgroup$– Rubio ♦Commented Apr 13, 2019 at 14:32
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1$\begingroup$ @Rubio ok. Thanks for your opinion. Sorry, mkinson! $\endgroup$– Mr PieCommented Apr 13, 2019 at 17:22
Answer is
3
Explanation:
5 Ds
5 Cs 5 Bs
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2$\begingroup$ please explain your approach to this answer. thanks and happy puzzling ;) $\endgroup$ Commented Apr 14, 2019 at 13:30
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$\begingroup$ You can add spoiler tags by putting >! in front of each line, and add 2 spaces behind each line to leave a new line. Thank you and have fun! $\endgroup$ Commented Apr 14, 2019 at 13:32
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$\begingroup$ But what about the A's? since there is 1 A, then it means the number of letters don't matter. $\endgroup$– SensorayCommented Apr 16, 2019 at 19:56
Answer is:
1.
explanation:
If you look diagonally from right to the left you have always one shape or letter in common and never same sign one after another so the correct answer is 1.
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$\begingroup$ Given @Svenpošta's answer, this might be correct, but with a different reasoning. Whaddayaknow! :P $\endgroup$– Mr PieCommented Apr 14, 2019 at 17:40
The answer is
option 2.
Because
There are 8 pairs in this picture. Each square gets paired with another one, if they have only ONE difference (either shape or letter).
For example, if we number each square from 1 to 16, top left to bottom right, we can see that these numbers are paired: (1,12), (2,14), (3,9), (5,8), (6,10), (7,13), (15,16). Then the only pair left is (4,11) and the only option that can be paired with square 4, is option 2.
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$\begingroup$ Why not (1,16)? Or, crucially, why not (4,10) or (4,13)? $\endgroup$– Rubio ♦Commented Apr 10, 2019 at 22:10
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$\begingroup$ There are other pairs as well and I just wrote those as examples. But you should be careful to choose pairs in such way that all squares can get paired provided the choices given. In any case the only option that can do so is option 2. You can check. $\endgroup$ Commented Apr 11, 2019 at 5:49
I believe that forms that are added to the letters are not relevant to sample detection.
The letters can be replaced by numbers in two ways (A = 1, B = 2, C = 3, D = 4)
2 4 2 4
4 2 3 1
2 2 1 3
3 3 4 4
or (A = 4, B = 3, C = 2, D = 1)
3 1 3 1
1 3 2 4
3 3 4 2
2 2 1 1
irrespective of how the letters are replaced by numbers, the sum of the two rows from the top and bottom are equal, such as the same are sums of the two columns on the right and on the left.
So the answer:
number 4 is correct (A missing)