Find the value of 'a' and 'b' in the following series.
100,101,120,103,410,321,205,404,60a,5b2
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$\begingroup$ may be a = 3 , b=3 $\endgroup$– Saurabh PrajapatiCommented Apr 24, 2015 at 11:42
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1 Answer
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Sum of all digits in every number is growing.
Number digits SUM
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100 1
101 2
120 3
103 4
410 5
321 6
205 7
404 8
60a it should be 9 so "a" = 9-6 = 3
5b2 it should be 10 so "b" = 10-5-2 = 3
