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There is a letter leaving two letters of the alphabet in order, after the letters placed at odd-numbered positions and leaving one letter of the alphabet in order after the placed at the even-numbered positions.

  1. ADFIKN
  2. BEGJLN
  3. CFHKLO
  4. DFIKNP

I need help in understanding this puzzle and in solving it. I have to choose an option which satisfies the given condition in the question.

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  • $\begingroup$ Answer is ADFIKN. A(2)D(1)F(2)I(1)K(2)N. here 2 means 2 letter's space $\endgroup$
    – Saurabh Prajapati
    Commented May 7, 2015 at 12:14

1 Answer 1

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The answer is

ADFIKN

as 

A(BC)D(E)F(GH)I(J)K(LM)N
   2   1    2   1    2
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