# Yet another mixed sum

An instance of this puzzle is here: https://www.theguardian.com/science/2020/nov/16/can-you-solve-it-the-srcmalbed-nmebur-plzuze

a) It has been swhon taht to raed a txet the oedrr in wihch the lrtetes of ecah idniadiuvl wrod aepapr is not ipmotanrt, so lnog as the fsrit and lsat ltetres are the crorect oens. Tihs is not the csae wtih nmuebrs baecsue if one slcarbmes the ditgis of a nmbeur it is not psisolbe to wrok out waht the ogirianl nemubr was.

Tehre are, hevoewr, cirtaen cesas in wchih tehre is sifuficnet inmoartfion to fnid out the onriiagl neumbrs if olny the interior diigts of ecah of them wree mxied wlihe the fsirt and lstt digtis wree lfet untaelred. Scuh is the csee in the fonlwloig aditiodn:

73,932
27,381
47,[2]63
+54,605

212,091

Can you rseotre the oigrianl atdiiodn and its sum?

(Hint: That lonely red 2 [marked by brackets] is where it should be.)

b) Without the hint of the lonely red 2, there are 13 solutions to the above puzzle. Can a similar puzzle, with a unique solution, be devised, with four five-digit summands, one six-digit sum, and preferably no number with interior digits repeated?

73932
27381
46273
+54605
------------
202191

## Process for a):

First started out by noting the sum of the digits in the ones column to be 11, meaning 1 will be added to whatever digits are placed in the 10s column. I then looked to the sum of the digits in the 10,000s column and on its own it equals 18. Since we know the overall sum has a 2 in the 100,000s column 2 or more must be carried over from the 1,000s column into the 10,000s column.
From there I looked at possible combinations of numbers that could go in each column and sum to a value that is a part of the final answer (0, 1, 2, 9). Starting from the 10s column since we know 1 will be carried over from the 1s column and then slowly working up the columns listing possible values. After I had all possible values listed I scanned for further possible ways to cancel out options. Finally, I looked at the remaining column options I had and looked for a combination from each column that could be validly combined without using the same numbers twice or missing any required numbers. This led me to my final solution.

## Solution for b)

$$\begin{array}{cccccc} &5&9&1&2&3 \\ &5&9&1&2&3 \\ &5&9&1&2&3 \\ +&5&9&1&2&3 \\\hline 2&3&6&4&9&2\end{array}$$