3
$\begingroup$

I have a set of words. If those words follow a certain rule, they become an Equal Word™. Use these examples to find out the rule for an equal word.

$$ % set Title text. (spaces around the text ARE important; do not remove.) % increase Pad value only if your entries are longer than the title bar. % \def\Pad{\P{0.0}} \def\Title{\textbf{ Equal }} % \def\S#1#2{\Space{#1}{20px}{#2px}}\def\P#1{\V{#1em}}\ \def\V#1{\S{#1}{9}} \def\T{\Title\textbf{Words }^™\Pad}\def\NT{\Pad\textbf{Not}\T\ }\displaystyle \smash{\lower{29px}\bbox[yellow]{\phantom{\rlap{rubio.2017.02.04}\S{6px}{0} \begin{array}{cc}\Pad\T&\NT\\\end{array}}}}\atop\def\V#1{\S{#1}{5}} \begin{array}{|c|c|}\hline\Pad\T&\NT\\\hline % \text{ MAN }&\text{ CLEAR }\\ \hline \text{ BALANCED }&\text{ WAVE }\\ \hline \text{ ORDER }&\text{ HIDE }\\ \hline \text{ FINE }&\text{ DJINN }\\ \hline \text{ EQUALS }&\text{ LINEAR }\\ \hline \text{ STAND }&\text{ STAIN }\\ \hline \end{array}$$

Improve this question
$\endgroup$

1 Answer 1

Reset to default
2
$\begingroup$

I think the rule here is

The sum of the positions of each letter in the alphabet should be an even number.

For example:
MAN: 13 + 1 + 14 = 28
STAND: 19 + 20 + 1 + 14 + 4 = 58
BALANCED: 2 + 1 + 12 + 1 + 14 + 3 + 5 + 4 = 42

The other words end up to an odd total:
CLEAR: 3 + 12 + 5 + 1 + 18 = 39
WAVE: 23 + 1 + 22 + 5 = 51
STAIN: 19 + 20 + 1 + 9 + 14 = 63

Improve this answer
$\endgroup$
3
  • 5
    $\begingroup$ Hm. If so, HIDE and EQUALS should swap sides. $\endgroup$
    – M Oehm
    Commented Sep 10, 2018 at 11:21
  • $\begingroup$ ah yes you're right $\endgroup$
    – Pim Schwippert
    Commented Sep 10, 2018 at 11:32
  • $\begingroup$ Even with the typo you got it correct! Well done! $\endgroup$
    – Rohit Jose
    Commented Sep 10, 2018 at 15:26

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service and acknowledge you have read our privacy policy.

Not the answer you're looking for? Browse other questions tagged or ask your own question.