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I have a mysterious sequence for you...

$204, 186, 172, 133, 126, 123, 120, 119, 111, 107, 102, 96, 90, 87, 86, 86, 85, 79, 75, 73, 70, 68, 66, 66, 65, 65, 65, 64, 64, 64, ...$

This sequence may change over time, so I made a website that (should) always show you the current sequence. It's not that likely to change often so the website only updates once a day.

https://puzzleforthepuzzlers.pythonanywhere.com/

Question: Find the next elements of the sequence.

Hint 1:

You won't find any hints in the source code or the domain or server response or something like this. It's really about the sequence. If it couldn't change, I would not need any server.

Another small hint:

The title of this question is a hint.

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  • $\begingroup$ Hopefully not too easy. ;-) $\endgroup$
    – palsch
    Commented Jun 9, 2016 at 16:45
  • $\begingroup$ What is the question? $\endgroup$
    – Gordon Allocman
    Commented Jun 9, 2016 at 16:46
  • $\begingroup$ @GordonAllocman Sorry, edited. $\endgroup$
    – palsch
    Commented Jun 9, 2016 at 16:46
  • $\begingroup$ Well I've officially changed the sequence. Some were quite good that I hadn't seen before! $\endgroup$
    – NoseKnowsAll
    Commented Jun 9, 2016 at 18:26
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    $\begingroup$ -1 This puzzle is based on a snapshot in time that cannot be seen later by interested parties. Even now, just a few hours later, it's not possible to verify. $\endgroup$
    – Set Big O
    Commented Jun 10, 2016 at 2:24

1 Answer 1

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It looks like:

It continues (as of now) ..., 63, 63, 62, 61, 60, ...

Because it is the number of votes (up minus down) of the top-rated questions ever on this site.

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  • 2
    $\begingroup$ Damn, I knew it is too easy. $\endgroup$
    – palsch
    Commented Jun 9, 2016 at 16:47
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    $\begingroup$ But interesting to look at. Only one at 200 so far! $\endgroup$
    – Dan Russell
    Commented Jun 9, 2016 at 16:49
  • $\begingroup$ @DanRussell only single one over 200 :0 $\endgroup$
    – ABcDexter
    Commented Jun 9, 2016 at 17:04
  • $\begingroup$ And credit to @Alconja for 3 of the first 6! $\endgroup$
    – Dan Russell
    Commented Jun 9, 2016 at 17:25

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