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Is it possible to completely fill the infinite tetris field $\mathbb Z^2$ with tetrominoes such that no tetromino borders another one of the same type (even if rotated)?

Assume that two tetromiones border each other if their blocks (squares) share at least one edge, not just one vertex.

Is it possible to completely fill the infinite tetris field $\mathbb Z^2$ with tetrominoes such that no tetromino borders another one of the same type (even if rotated)?

Assume that two tetromiones border each other if their blocks (squares) share at least one edge, not just one vertex.

Is it possible to completely fill the infinite tetris field $\mathbb Z^2$ with tetrominoes such that no tetromino borders another one of the same type?

Assume that two tetromiones border each other if their blocks (squares) share at least one edge, not just one vertex.

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  • 92

Is it possible to completely fill the infinite tetris field $\mathbb Z^2$ with tetrominoes such that no tetromino borders another one of the same type (evereven if rotated)?

Assume that two tetromiones border each other if their blocks (squares) share at least one edge, not just one vertex.

Is it possible to completely fill the infinite tetris field $\mathbb Z^2$ with tetrominoes such that no tetromino borders another one of the same type (ever if rotated)?

Assume that two tetromiones border each other if their blocks (squares) share at least one edge, not just one vertex.

Is it possible to completely fill the infinite tetris field $\mathbb Z^2$ with tetrominoes such that no tetromino borders another one of the same type (even if rotated)?

Assume that two tetromiones border each other if their blocks (squares) share at least one edge, not just one vertex.

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  • 49
  • 92

Fill up a tetris field where bordering tiles have different colors

Is it possible to completely fill the infinite tetris field $\mathbb Z^2$ with tetrominoes such that no tetromino borders another one of the same type (ever if rotated)?

Assume that two tetromiones border each other if their blocks (squares) share at least one edge, not just one vertex.