Especially Lime
• Member for 5 years, 3 months
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247 views

Once you can identify which symbol means &quot;equal&quot;, this reduces to the original problem. That is because if you follow a valid strategy assuming that A means &quot;left heavier&quot; and B ...

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MichaelMaggs' answer is generally reasonable but misses one vital point:

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Consider the following cases: There is an egg in A There is no egg in A, but exactly one in B or E There is no egg in A, B or E, but exactly one in C or I There is no egg in A, B, C, E or I, but ...

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I must have missed the trick somehow. You can fill in a few 1/2/3/4s straight away. After that there are only two spaces left in the top right, which are 8/9 in some order. I tried the one that seemed ...

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Suppose there are $n\geq 3$ chips. It's easy to see that $n$ moves is possible, making each move exactly once (this flips each chip three times). Since making the same move twice cancels out, any ...

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A slight improvement to Misha Lavrov's answer. Unfortunately I don't think this can be pushed any further:

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I disagree with most of the other answers - I think it is a better question than most actual IQ test questions. The point is that if you haven't seen something like this before, then whether you're ...

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Suppose there are $R$ red lamps and $150-R$ blue.

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Suppose black passed. White could easily win in three moves: c3 forcing e3, then d4 threatening to create either of two squares. White could also use the same tactic starting with e3, c7 or e7. If ...

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Well, the most obvious explanation for Ms Salem is that she rejects There are probably several possibilities for Mr Spencer, but I can't find one that seems as natural as the above. Certainly it's ...

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Suppose that the guns, and order of turns, have already been determined. There are only two plausible strategies for the player with the bad gun: either they always shoot at the player with the good ...

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As JNF says, your mother must have AB parents and be BB herself. Applying the final point directly to your father, before taking into account information from your own blood type your priors for his ...

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Here's a question which I think works. Explanation: (Note: I came up with this without reading the extra "warming up" section, so my question doesn't produce the exact same table that you had, but ...

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I think this works. The line used between each two stops is in brackets. Oxford Circus (Victoria) Green Park (Picadilly) Picadilly Circus (Bakerloo) Charing Cross (Northern) Embankment (District) ...

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elias's strategy for is optimal. To see this, note that

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I think there's a quicker way to do it. for 12 moves.

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I see Evargalo has found the right answer, but the first thing that occurred to me was

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If cuts are allowed to meet the perimeter between the start and end, as in Peregrine Rook's answer, the best you can do is You can't do it with fewer. Of course, if cuts aren't allowed to hit the ...

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hexomino is correct that there's not a safe way to proceed, but the heuristic doesn't give the right probabilities for the remaining squares. Looking at the top five unknown squares, there are five ...

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Here's a method with three questions that is less artificial than boboquack's solution. I'll assume there are four people in a line, (left)ABCD(right). First, tell everyone "I'm thinking of a ...

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They are all In order

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The reverse of Beastly Gerbil's solution also works: These are the only two possibilities.

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Artur's proof is very nice. I did it a different way. First, note that it is sufficient to prove that for any C it is impossible for the genius to take more steps of cost at least C than the idiot. So ...

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