DooplissForce
• Member for 5 years, 7 months
• Last seen more than a week ago

You say because

I can do it in folds, by

Perhaps it was

This is kinda cheap, but:

To decrypt these, we can use

Perhaps it's:

It's since

First: Second: Third:

Not sure if this is a valid solution either, but

Perhaps it's:

Are you: I have many friends / Some of which you know I know sans, but not papyrus Sometimes people think I can be Italian / But in reality I can only be quite loud I excel in many things / And ...

That morning, Scrooge

This should work: Method (if you could call it one):

Are you

Obviously, $64\neq65$. Observe the diagram below: The slopes of the diagonals of the blue and pink pieces are each $2/5 = 0.4$, whereas the slopes of the diagonals of the green and red pieces are ...

(Partial answer) Adding onto rand al'thor's answer, I rearranged them so all the blue shapes matched up: Stealing from rand, the red shapes make: Another observation:

It is:

Is the first one maybe:

I got Short way: Long way: For $CNS(945)$: For $CNS(947)$:

A possible six (without anagramming):

It's

To add on to what everyone else has, here's the grid marked up with everything I've found so far: Edit (7/15 8pm EST): Updated the grid with Poolsharker's bridge:

Adding onto what people have, the second is And given the other answers and the context of the story, I can assume that the last word will be

I'll use the diagram below while I'm solving this: Let the radius of the larger circle equal $r$. First, the area of the red section ($A_\mathrm{red}$). This can be found by using the formula for ...

They are:

I think it could be

Some I can think of are:

The sequence is: The next five numbers in the modified sequence are: And the modified sequence is:

Is it maybe

The groups are and the disqualified vote is My method: At the suggestion of @Matsmath, if we started with the disqualified vote: