Carl Löndahl
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An upper bound Bob picks a random permutation of the deck and then rotates the subset of his deck that does not match Alice's. The worst case is when the whole deck is a rotation of his initial ...

The answer is because that becomes Explantation:

Since the answer already has been accepted I would add this as a comment, but I do not have sufficient points to do so. I agree that the answer should be... but due to the reason that...

This will require since Here is a graphical representation Here is a simulation import random E = 0 for j in range(0, 20000): s = "" i = 0 while True: i += 1 s += ...

If we consider them to be Here is an image

This is a sketchy proof of what Ivo suspected in the comments. Take an arbitrary selection as below. $A+B+E+F = 0$ $A+B+I+K = 0$ $=> E+F=I+K$ $E+F+I+K = 0$ $=>E +F = -I-K$ $E = -F$ $I = -... View answer Accepted answer 10 votes I believe it is Since View answer 9 votes This is a long shot but here goes... What loves to talk but has little to say Nags you in the morning and throughout the day View answer Accepted answer 9 votes I am the square of 1514, but actually, I'm just the square of 4. I possess a property, where women could be burned for in my time View answer Accepted answer 9 votes The numbers correspond to The phrases are The complete list: They are ordered by View answer 8 votes Because: View answer Accepted answer 8 votes 4 is partly covered by 0 0 is completly covered by 3 6 is partly covered by 0 6 is partly uncovered by 0 4 is completely uncovered by 6 4 is partly uncovered by 3 6 is not covered by 4 So we need a ... View answer 8 votes Turns out there are two solutions:$171$and$341$(unless I made a terrible mistake; I have checked this using some Python code). L = [1,2,4,8,16,32,64,128,256,512] Q = [0]*(sum(L)+1) def rec(Q, L, ... View answer 7 votes View answer Accepted answer 7 votes This gives View answer Accepted answer 7 votes Possible answer: Because Example View answer 7 votes Update Going back to my original post where$f$is defined as This is explained as follows: Let$*****,y_1,y_2$be an arbitrary number. If$y_2$is 0, this cannot be further expanded. So we ... View answer Accepted answer 7 votes or Therefore, Of course, there are many possible solutions to this question... View answer Accepted answer 7 votes 10. 11. View answer 6 votes E: View answer Accepted answer 6 votes The word is since she View answer 6 votes Here is another take. We can use the modulus$53$using only operations$(+,-,x)$, simply by removing$53$until we have reached a non-negative number strictly less than$53$. Let$a,b,c,d,e \in \...

Making the events independent, we get a probabilty that is $p_{i,j} = \mathbb{P}(\text{player }i\text{ wins }j\text{ games}) = {6 \choose j}\cdot 2^{-6}$. (note: if six players wins 3 games, then ...

The probability is given by $P(fair|heads^m) = P(heads^m|fair) \cdot P(fair) / P(heads^m)$, where $P(heads^m) = P(heads^m|fair)\cdot P(fair) + P(heads^m|nonfair)\cdot P(nonfair) = 1/2^m \cdot K/N + 1^... View answer Accepted answer 5 votes The question did not state no computers, so I guess this answer is as good as any other. ...gives... which gives a score of 389. This is using the Merriam-Webster dictionary. No word is an anagram ... View answer 5 votes The answer is probably since the boxes move as follows ...at least that pattern matches and it is reasonably simple. View answer Accepted answer 5 votes Here is a somewhat sketch proof for (1) that may be missing some less obvious details: Some graphical example: So... For (2) even sketchier... Some more badly-drawn graphics: To... View answer Accepted answer 5 votes I mapped the symbols to$\{0,1,2\}\$, so we get: 011 | 221 | 022 001 | 120 | 011 222 | 001 | 120 ----------------- 210 | 210 | 210 212 | 201 | 122 001 | 120 | 010 ----------------- 020 | 012 | ...