New answers tagged

3

Full Solution (solved by Michael Moschella) (solved by Michael Moschella) 3. 4. 5. 6. 7. 8. 9. (solved by El-Guest) 11. 12. 13.


2

1 2. 13.


2

10.


7

The phrase Is an anagram of


2

6 words, 5 letters 5 words, 8 letters (longest out of these answers thus far, however) 5 words, 6 letters 5 words, 5 letters (apparently there are many more, but these are the 100% non-obsolete words)


4

I am... You seek him who died at sea, Try and find who he might be. A heart that did not wilt in flame, Writ on Roman stone is his name. Nothing of him that doth fade, But doth suffer a sea-change, Into something rich and strange. Now with his Adonis he lies, Who thought not himself worthy of fame, And writ on stone not his name, That lies beneath lit ...


2

The wrong answer is explanation: We are just some of many One of us on every line Don't jump to conclusions Or there'll be confusion Make it right and you'll be fine


1

Based on the last line, If you work with bites... The third line:


12

I think you are a If you snatch, I trade. If you work with bites, I isolate, If you work with celestial bodies, part of me protects. If you work with the land, I divide.


18

She has


9

Here it is, no explanation needed i think :) Note: As @IvánNokonoko mentioned in the comment, the NNE grid in the second layer (from outside) can also be R instead of A to form (GRIT and BRIT). Thanks!


6

Edit: The words in NNW are and not since we already use These are the answers going anti-clockwise: Also, something extra:


1

I am a visionary. Score: 7 words (8 numbers) Inspired by


17

Start with eleven in one e four e six; add what is missing from otherhood, oke, icks; improving position, go upwards by one; mix up for organs, remove fifty-one. Add to the end an American nation; abbreviate all and add short operation; age for a few more years, then turn around; prefix by fifteen – a trap on the ground!


5

Very Partial answer... Only solving part of a stanza... Start with eleven in one ee four ee six; add what is missing from otherhood, oke, icks; improving position, go upwards by one; remove fifty-one


1

Building off the answer by @El-Guest:


4

Since he has 117 116 75 66 74 71 73 117 116 77 100 160 120 174 63 44 72 60 162 100 174 134 174 46 63 44 73 Could it be possible that the password is


20

Righteous head of a snake that is a snake, Aback, held in a fish that is not a fish. Now, I'm beauty in disguise, Despite being, to most, nightmarish. Second connection


8

I thought you were jafe, but looks like you might be I am within my rights to stay silent. I am abandoned in the middle. I am held in by spirit. I am African capital.


7

I hope my initial thoughts for your puzzle are I hide as a puzzle in Malaysian spoon, Bounding sturdy monument and sturdy wood. Upside-down in common marsupials' and rare antelopes' front, I'm a gesture, or three, for good.


3

Very partial answer I hide as a puzzle in Malaysian spoon, Bounding sturdy monument and sturdy wood. Standing upside-down in marsupials' and antelopes' front, I'm a gesture, or three, for good.


12

I really hope the answer is In a creature is my natural home. Have me in your meal and you'll become me. (With me, this line would be adjacent.) Experts take more time with me. In winter wear, I might be half a mile. Title: I wish, I yearn, for an answer to this riddle


11

I have made films on wood. I have stopped by a park. Going outside late makes me happy. I'm yearning in grey.


0

Are you just looking for


6

22 Steps using Knight -> Rook and Queen -> King from jafe's answer


6

25 steps


12

This is a proof that Omega Krypton's answer of 38 is optimal, as long as these words are nonexistent (single implication): EEVEN,EINE,ENINE,FIUR,FIVR,FOVE,NIGE,NINH,OWO,,SEGEN,SEVET,SEVHN,SIVEN,TNO,TWE First, a calculation of the theoretical best (although no suitable words may exist), by using a Levenshteins distance (word difference by letters) ...


6

39 steps (40 words): Word 6 courtesy of @Gareth Definition of less-known words:


2

Without using somewhat obscure words, there is no way to go from EIGHT to SEVEN. (12 steps) with one rare word (the same as what @Gareth McCaughan got): The rarish word is asterisked. To find this I used a program which knows the rarity of each word (via the SCOWL word list) (11 steps) allowing rare English words (rare words asterisked): Allowing ...


11

Best solution so far: 38 steps 9-7 from @Gareth, and sien from @devyndraen thanks!


14

Here's one way. It probably isn't close to optimal. 42 steps if I've counted right. Credit where due: the path from EIGHT to SEVEN is derived from Hunter's answer to an earlier puzzle, though not much of that answer remains in what I have there now. JonMark Perry spotted what in hindsight should have been an obvious improvement in the path from FOUR to ...


3

Based on SlowMagic's answer I have managed to fill in the rest of the diagram


3

This is longer (12 steps) than the other solutions here but uses only words I can actually define (and that aren't proper nouns or words only in other languages like "Old English" which despite the name really shouldn't be considered the same language as English). Anyone got a shorter ordinary-words-only solution?


6

Eight step solution


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Six steps - Shameless use of Old English with Wiktionary support: Ten steps - If you insist on using Modern English, here is a shortened one highly based on @Gareth's:


15

Here's my 8-step solution: (I don't know if SINHS - plural for SINH ("hyperbolic sine function") is an accepted word)


9

I guess I am just not very good at these puzzles... the solution I found is 3,001 steps long without repeating any words.


7

Four, but using more ancient spelling (where U and V were interchangeable)


9

As @RossMillikan pointed out correctly, the proof from @TheSimpliFire is incomplete. The following part F i v e, F _ _ _, F _ _ _, F _ _ _, F o u r. Therefore, at each step, one of i v e must be changed to match o u r, without any deviations. This is clearly impossible. can be done with any of the following sequences Five => F_ve => F_ue / F_vr => F_ur ...


10

In this answer I will show that five steps is the minimum number required (from the answer by @JoãoBravo). Suppose by contradiction that there are four. Then the sequence will be of the form F i v e, _ _ _ _, _ _ _ _, _ _ _ _, F o u r. If the first letter remains unchanged the whole way through, the sequence is F i v e, F _ _ _, F _ _ _, F _ _ _, F o u r....


34

Just signed up to share some of the solutions (3 of them) I was able to come up with in 6 steps: OH MAN! After a lot of searching I was able to do it in 5 steps (5 solutions): I confirmed the words on Anagrammer. EDIT: although all words are accepted on Anagrammer, someone pointed out in the comments that two of the words used in the 6-step solutions ...


5

Seven steps (with some obscurer words): Something that might lead to five, if it can be completed: That's three steps from FIVE to something that shares two letters with FOUR.


5

I found a solution in seven steps.


7

I can do it in With one more obscure word, I can do it in


18

My first is in Family and also in Hill My second in Circle and also in Flood My third is in Forest and also in Clock My fourth stands alone in my frozen wastes. These together make First Try: Selecting letters for No. 1, No. 2, etc. I'm not sure if this holds water but is it an Title: Frozen Wastes


0

Maybe a better clue for 1 could be Dog primitively routinely underestimated by online games! (5) Since


5

5) 6) 15) 19)


11

FULL ANSWER: 1) 2) 3) 4) 5) 6) 7) 8) 9) 10) 11) 12) 13) 14) 15) 16) 17) 18) 19) 20)


4

Partial answer 2 7 8 11 13 14


7

Partial Answer thanks to Ak19 and pirate for their contributions! 1) 2) 3) 4) 5) 6) 7) 8) 9) 10) 11 12) 13) 14) 15) 17) 18) 19) 20)


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