Solution (click to see large version):
The first thing is to produce the following list:
I: 1234 6789
II: 23 78
III: 3 8
From that, standard Sudoku techniques apply. I'll just list some middle steps below.
Should've known what I'd gotten myself into when starting, whew. Great puzzle! Really hard, but I hope I got everything right.
0th Step: Try to squeeze out everything we can by normal Sudoku first:
This is a fantastic puzzle! Incredibly difficult, but with a really nice solution path. I have no idea how you managed to come up with this!
How to solve:
(This took me about 7 hours so my memory of early logic is fairly rusty, but I have explained as best I can)
And finally, cleaning up the right hand grid and entering ...
I used the exact same logic for each picture here:
With that in mind, some pictures, in order. I mostly completed two regions per picture.
Step 6 (and the solution):
Not hard but quite enjoyable.
Looking at the X:
Some more logic in the upper left:
The pentomino on R4C4:
A quick Sudoku hit:
Place the F:
Finishing the pentominous:
Back to Sudoku:
Continuing in the lower right:
Repeatedly iterating over the boxes (regions?) gave me:
Then, doing the same over the columns gave me:
All in all, this was a great puzzle! The gaps in the board made it a little tricky to keep track of how some numbers blocked certain spaces, but it was still very enjoyable. Looking forward to more of the series! :) This was a pretty straightforward solve,...
(Will try and put into excel and clean up the images when I have the time)
Starting off, we can make some quick and easy deductions:
Moving on, there are a lot of hidden singles throughout the grid
Even more hidden singles later...
And the solution:
Keeping the numbers and filling in the obvious cells gets us this starting point:...
The first thing to note is that some standard sudoku principles apply.
For example for each row and column as well as each block can only contain a particular digit 3 times in each place.
I will use notation [row,column].
To start off we can notice that in the fifth row all 3 of the right zeros ( -0)
are filled in so entry [5,4] (2-) must be equal to 22 ...