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8

For a scramble to be any good, at the very least you would want every pair of adjacent pieces to become separated at least once during the scramble. You don't want any blocks to remain unscrambled, because that would make it slightly too easy. Here is a very rough calculation of how many moves this takes. There are $48$ pairs of adjacent pieces ($6$ cutting ...


6

There is nothing special about the solved state. Solving the cube means achieving a particular permutation of the cubelets' faces; that's true whether what you're trying to end up with is the state we call "solved" or some other state; God's number is just the maximum number of operations you need to do to achieve any achievable permutation of cubelet faces.


1

Learning full CFOP is tedious, because if you remember 70% of the "orient last layer" algorithms, and 70% of the "permute last layer" algorithms, you'll be unable to solve the last layer more than half the time. So the hard work is going to be memorizing the OP bit, and then you'll be still in the same situation with committing all the OP algorithms into ...


1

The cube is not solvable normally from this position. A piece must have popped at some point and been replaced incorrectly. The fastest way to fix it from here is probably just to pop them again.


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