White must Indeed Note that


Since the puzzle turned out to be way hairier than expected, my earlier answer got quite messy and hard to follow, so here's a complete rewrite. It's still very clunky, but I hope it's much clearer than the earlier one. Also, there's an executive summary at the end, if you are not interested in all the gory details. First, we'll need to make some general ...


Now that we have three increasingly complex proofs (two deleted, one of them mine) that it's impossible, it's pretty clear that it must be Here's why: This is, without doubt, the most refreshing chess problem I've ever tried to solve. Thanks, OP!


I see Evargalo has found the right answer, but the first thing that occurred to me was


Here's a solution: Here's some of the logic for finding it: Here's a link to the moves: Clear the board! And here's a gif (thanks to chess.com's gif maker):


(Edit: so this is wrong..) Brilliant puzzle! The answer is: [Spoiler alert! Scroll down at your own risk] We proceed by contradiction. Assume that indeed, White can castle. We have the following undeniable facts: Neither the White King nor the White h-Rook have moved. Since neither of them have moved, the only way the Black Rook could have gotten to ...


I claim that The reason:


The word that doesn't belong is The crossword looks like this: How I solved it:


This seems to work: And the position looks like this: Apart from the symmetrical solution, this might very well be unique:


Featured in the past, compositions by musical uncle Francis, at: Handbill: La-Fa-Sol-Do-Re Ti-Fa-Sol-Do-Re Ti-Ti-Do-Sol-Mi-Re Sol-Do-Do-Mi-Sol Sol-Ti-La-Fa-Mi-Re-Mi-Re Ti-Fa-Sol-Do-Re La-Ti-Do-Fa-Mi-Re Fa-La-Ti-Mi-Sol Sol-Ti-La-Fa-Mi-Re-Mi-Re Mi-Mi-Sol-Mi-Sol La-Ti-Do-Sol-Mi-Re Fa-Do-Ti-Mi-Sol Sol-Do-Mi-Re Do-Mi-Re ...


It is currently: because All that means it is now the


Oooh, that's a nice one. First of all, Further more, it's a mating move by I first tried (in vain) to So it must be It turns out that with the following moves: Final position:


HTM's answer is very nice and must be what's intended here. But I'm not quite seeing why the puzzle isn't cooked as follows:


Not exactly a checkmate, but there is an option with a similar effect that can be performed in zero moves:


Note that without their king, White’s plan would be Thus, the aforementioned sequence of moves will The only square White’s king can be in that satisfies the constraint is


In the position shown, Now, Before that Black White So we have the following sequence of events. Now, We still haven't figured out Suppose that Now So let's consider We must now be quite close to having nailed down So far, so good. But black Aha! Therefore white's last move was It's possible that some of the reasoning above can be pruned ...


I found the following: The key is that


Well, for the mate in 1, For a mate in 2, An assured path to victory: As to the final question: EDITED after the sudden appearance of the corner knight: The stuff in the spoiler tags got shuffled around too, so let's recap:


rand al'thor points out that and since the numbers are but after the square marked 16, Robert's got this (image courtesy of OP) and we can now see why Robert is distressed: ... which is a situation that always frustrates me, though I don't get quite as angry...


I suspect the broken rule is Allowing the checkmates A hint pointing to this answer:


This solution is no longer valid. The original posting of the problem had a typo (and lacked the restriction of "no auctions"); with the typo, at least one auction was required to solve, and this answer provided such a solution. For the corrected problem, @dcfyj's post provides the correct answer. It is Player 1: Battleship's turn Here's how the game plays ...


It is: Reasoning:


The other guys already got the answer. (Maybe not with completely airtight arguments, but nevertheless.) The explanations would be a lot easier to follow if they had pictures, so here's one: Legend: Red square: after turn 1, you are in one of these. Green square: after turn 2, you are in one of these, or in some red square (except square 2). Red circle ...


The answer is Reasoning: So This could only happen White's f and g pawns So would be


Since the rook and the bishop are in a threatening position for both kings, they must belong to the same color. I can see but one explanation for this: and the last step was As to how a mate in two was possible from here, let's assume the colors were like this: Then Megan could have been mated with: (From the story we can assume that Megan probably didn'...


This one has the checked king. It is about the linking of knight captures.


As requested by @KeyboardWielder in a comment on my earlier answer After much back and forth, and investigation of the structure of the code using the print-to-console debugging technique passed down through the ages, Ananda and the Master had come to the following conclusions: The lines of the input file were being read in the correct order. The input ...


To add on to Glorfindel's answer,


Are you playing If so,


6 rounds have been played and no-one has any voids before you sit down. There are therefore at most 1 round of spades and hearts (if there were 2 then 8 cards are played + 4 visible + 2 with the opponents =14), and 2 rounds of diamonds and clubs. The only way to get to 6 is if exactly those were played, meaning that before you sat down there had been 1 ...

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