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2

I don't think this is possible to exactly solve, but here is my attempt with probabilities, which leads to a complicated expression (which I have not quite worked out yet):


0

Literally thousands of answers. Dish1 costs (price1) 1 Dish2 and Dish3 cost (price2, price3) a prime number greater than 3 where price2 != price3. If either price is 3, the other cannot be 2 or 5.


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