21 votes
Accepted

Making three fair dice

Manish Kundu's user avatar
  • 2,424
21 votes
Accepted

Making two fair dice

This seems to work: Whichever we throw first,
Jafe's user avatar
  • 71k
9 votes

Making two fair dice

If I believe
Sneftel's user avatar
  • 2,655
7 votes

Making two fair dice

Surprisingly, this works if and only if you divide the pips evenly between the dices! Let us take one of the dices and denote its numbers by $\sigma_1,\ldots,\sigma_6$ (in increasing order). Then, the ...
gerw's user avatar
  • 171
6 votes
Accepted

Making fair dice

You can't do it for Or for It is possible for Finally, it's not possible for So the answer is
Especially Lime's user avatar
4 votes

Making two fair dice

Sneftel's sufficient condition is in fact not necessary. A different construction to achieve 50% win rate is the following. This construction does include some cases that Sneftel's doesn't (and vice ...
Especially Lime's user avatar
3 votes
Accepted

Intransitive urns

or
loopy walt's user avatar
  • 17.1k

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