61 votes
Accepted

Can you put L trominos to fill the figure?

Answer: Reasoning:
Magma's user avatar
  • 5,024
52 votes
Accepted

Tiling with T-tetrominos in gravity

TLDR: I'll fill the board and prove that the solution is unique. First, let's start by: I'll paint those green: Let's repeat those steps a few more times, using orange, blue, red and purple, in ...
Victor Stafusa - BozoNaCadeia's user avatar
25 votes
Accepted

Now You're Packing with Portals #1

This works! (I think) (Hopefully that’s clear enough how the shapes go) I got this mostly by thinking about how the blue and red can be placed such that the top and bottom of the green can be ...
Beastly Gerbil's user avatar
22 votes

Tiling with T-tetrominos in gravity

I think that this tiling is a valid Tetris stack:
M Oehm's user avatar
  • 58.6k
22 votes
Accepted

A Rook's Territory in the Chessboard

I started with this: Pushed things this way and that, ended up with this: Similarly, on 9x9: And on 10x10: It took me a while to get there, but that one suggests an emerging pattern. And here is ...
Daniel Mathias's user avatar
21 votes

A Rook's Territory in the Chessboard

Here's an expandable solution for $n\ge 5$ (even or odd):
RobPratt's user avatar
  • 11.8k
21 votes
Accepted

Polly O'Mino's Hexcellent Adventure

COMPLETED GRID The first step: Next: An important side note: Moving on: The top shaded region: Hopefully, finishing up:
Jeremy Dover's user avatar
  • 26.3k
21 votes

How many distinct pentominoes are possible to place on an 8 x 8 board?

With integer programming, I managed to place like this. Here is my formulation. I happened to solve a similar model to solve a puzzle called One puzzle a day. Let $B$ be the set of cells in the 8x8 ...
xd y's user avatar
  • 525
21 votes
Accepted

Most polyominoes in an 8x8 grid

user1502040's user avatar
20 votes
Accepted

Near-fill with 3x1 long triominos, how to do a different void square than the center square?

The trick to this puzzle is to: (And here are those tilings: the center was already given, and the rest are obtainable from these by rotation.)
Deusovi's user avatar
  • 145k
20 votes

Covering an 8x8 grid with X pentominoes

The X-pentomino tiles the plane, so that tiling is a good way to start. There are two ways to cut an 8x8 region out of that tiling. If one of the 4 central squares of the 8x8 region has an X centred ...
Jaap Scherphuis's user avatar
19 votes
Accepted

Filling the plane with two colors

FINITE PORTION OF ANSWER This can be extended infinitely in all directions - see my route to solving below for how. First a detour to explain how I made a tool (which competing answers could also ...
Steve's user avatar
  • 3,845
19 votes

How many distinct pentominoes are possible to place on an 8 x 8 board?

I solved this completely by hand. Here is a clean proof of its optimality. No computer is needed. Mere pencil and paper suffice. Expand each pentomino by adding little right-angled isosceles ...
user21820's user avatar
  • 1,115
19 votes

How to fully tile an 8 by 8 square with Z-tetrominoes?

If reflections are not allowed: The figures below show why. If reflections are allowed: See figure below showing the top three rows of the 8x8 square.
ApexPolenta's user avatar
  • 2,166
18 votes
Accepted

Packing pentominoes in a circle

UPDATE 2 A minor improvement. New best radius Arrangement /UPDATE 2 UPDATE New best radius: using arrangement /UPDATE I get a radius of about using the following scheme which is obviously ...
loopy walt's user avatar
  • 19.1k
17 votes
Accepted

Polyominoes to construct alphabet

I haven't tried one of these before; I just stumbled across the question by accident. But I think I have an answer. You can build all 26 letters if you have a set containing: Image below:
Dave's user avatar
  • 186
17 votes

The universal ticket

The previously best-known solution has score of 165, with the following grid: From a clever brute-force search, one can learn that However, you can do better! The ticket achieves a score of
A. Rex's user avatar
  • 945
17 votes

How to fully tile an 8 by 8 square with Z-tetrominoes?

\begin{matrix} 9 &1 &9 &5 &5 &9 &1 &9 \\ 1 &-11 &-3 &-7 &-7 &-3 &-11 &1 \\ 9 &-3 &5 &1 &1 &5 &-3 &9 \\ 5 &-7 &...
RobPratt's user avatar
  • 11.8k
17 votes

Smallest rectangle to put the 24 ABCD words combination

Pretty sure that the following is minimal.
Ed Pegg's user avatar
  • 271
16 votes

Polyominoes to construct alphabet

Using:
JMP's user avatar
  • 35.6k
15 votes

Tiling with Js and Ls

UPDATE Down to 6 outcolour tiles Here is one way:
loopy walt's user avatar
  • 19.1k
15 votes

The universal ticket

Very unlikely to be optimal, but got to 120 on my first go: Approach: mess around with the problem until it becomes clear that connectivity of the squares will be the main problem. invent glue, ...
Bass's user avatar
  • 75.8k
15 votes
Accepted

The woefully underclued crossword

Answers to clues: At this point, given the tag, it looks like we are looking for So let's start filling the grid: Completed grid:
Amoz's user avatar
  • 24.5k
13 votes
Accepted

Four Birds + One

Challenge 1: Fit the four yellow birds into the tray, no overlapping. Rotation and reflection are allowed. Challenge 2: Fit the four yellow birds and the blue piece into the tray, no overlapping. ...
Oliver Ni's user avatar
  • 1,140
13 votes
Accepted

How many colors does it take?

I think the answer is using the following coloring: For other board sizes, Reasoning:
Glorfindel's user avatar
  • 27.9k
13 votes

What is the minimum-sized Blokus board which can contain all pieces?

Wow, that sure is tight. And yes, even though it doesn't look like it at the first glance, the I and T pentominoes are legally connected to each other :-) This took surprisingly long to find and (...
Bass's user avatar
  • 75.8k
13 votes
Accepted

Generating all hexominoes by cutting and pasting

phenomist's user avatar
  • 13.6k
13 votes

Packing pentominoes in a circle

I can get a radius of: Method: start with and then EDIT: I found a second solution with the slightly worse radius Method: start with and then I found both of these with the help of
Ravi Fernando's user avatar
13 votes
Accepted

Smallest polyomino adjacent to 3 copies

Assuming (like Retudin's answer) that smallest P means smallest polyomino, and that placements of polyominoes have to be perfectly grid-aligned: by With monominoes The reason why a domino solution ...
new Q Open Wid's user avatar
13 votes
Accepted

Fewest polyominoes adjacent to 3 copies

The minimum number of polyominoes needed is Proof:
Carmeister's user avatar
  • 1,801

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