I believe that entering 71 and tapping equals repeatedly should result in the number:
Why? Well note firstly that in each pair of 'equivalent' numbers:
Note that in the range 10-99, there are 90 numbers in all. These can be split into the following categories:
See also that for the 6 'partnerless' numbers listed in the puzzle (11, 14, 42, 50, 88, 89):
1) Middle is like "mirror" - or "Axial symmetry" if you like. So bottom left.
2) Similar puzzle answered here. Top right seems correct one - You count numbers each squares, and 1 yellow + 2 blue and 3 purple is missing. Same for each sides - three left, three bottom and two right, so it has to "stick" to right side of box.
3) Answered here
4) Seems like <-...
For this task, I would argue that it is important to ignore the black tiles. If you look at the blank space, the black will not provide pointers towards the logical conclusion (as there are no black tiles leading to the solution). There is consistency in everything except how the black tiles relate to other tiles.
My reasoning is the following:
How does ...
This is a tricky one! Some of the words could fit into many categories, but I think the final categorisation yielding four groups of four is:
The connection between these four categories is then:
As for the title:
There can be several answers to this:
Assume the following format : $$ d = (a + b)\times c $$ where, $a$ is the number of lines in the left end, b is the number of lines in the right end, and c is the number of intersection points between the "middle vertical line(s) and the horizontal lines".
Now, for $A: d = 28; B: d = 15; C: d = 24; D: d = 0; E: d = 32$
I don't think you can assume that there is an elegant, satisfying answer to this problem. If the people who provided the intended answer you cited are the same people who conceived the problem, there is obviously an error somewhere, possibly a mistake in the depiction of the "B" image. Unless you have reason to believe that this is a valid problem, and only ...
There are several ways one of the pattern differs from others. One for example
If you count ALL vertical and horizontal lines
A = 11
B = 9
C = 12
D = 9
E = 12
From this you can argue that A is the odd one out-- the only PRIME NUMBER or the pattern should have been 12,9,12,9,12. So A is the odd one
Another way is to count all ...
The ambiguity is not your fault, it's just the basic nature of all categorizing puzzles that provide way more object information (9 symbols per object) than categorizing information (5 bits total). There are only 32 ways to divide the grids into categories, but because there is so much information in the objects, there are many more simple ways to describe a ...