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4

I think the answer is, Reason


3

The missing number is Procedure for getting from one step to the next Other cases, step-by-step


2

I think the answer is Reason


5

The answer is You can generate this by


0

I think it is, Reason


-1

The next number is Because you are displaying the sequence: for which, the first 6 nonzero natural numbers $j = \{1, 2, 3, 4, 5, 6\}$ yields: This is the simplest and neatest solution because


8

The answer is: Because


1

The answer is For this kind of question, we cannot just simply split the terms as every term is connected to each other. Therefore, the logic is Here is the process: (3/2)*(2/3)=1 (2/3)*(3/4)=1/2 (3/4)*(1/3)=1/4 (1/3)*(3/8)=1/8 (3/8)*(1/6)=1/16 Hope this clarifies.


4

Obviously the answer is because That is, For odd: $3/2 \times 1/2 = 3/4.$ $3/4 \times 1/2 = 3/8.$ For even: $2/3 \times 1/2 = 2/6\implies 1/3.$ $1/3 \times 1/2 = 1/6.$


1

One possibility: As an aside...


2

I think the answer is Reason


3

My guess is Because Then


1

I think it's Reasoning


5

The oddball is because But


10

It's or or or or or


4

First, I define three functions: Those functions produce the values Then we can express the sequence like that: Giving and finally so the next element is


4

Well, it is which so the answer is


5

Edit: (Old answer removed, apparently it was confusing the issue)


0

Here is another offering.


3

Surely not the intended answer Jaap has of course identified the intended sequence. It seems to me that all the algorithms described so far are strictly more complicated than the following, which is simply another way of formulating the division operation and seems entirely straightforward to do in one's head. However, it can't be the intended answer ...


1

The next triplet is because (Thanks to @NoLand'sMan for pointing out in comments that I can't count.)


4

Jaap Scherpuis found the answer, but the OP wants more explanation and a simple construction... I am middle aged bike rider still in prime shape. I have twin like older brother who is couple of years older than me. We both are cryptographers who love to play with fractions and our digital signatures consisting of long sequences that are closely tied to ...


18

So the answer is I am not sure I have found the intended "key" and generating method, but one possible method is the following.


0

Answer Solution


3

The final grid is And the pattern is


4

The nth element of the sequence is Alternatively, if you use an offset such that the first term has n=2, you could say Source for the second solution: https://oeis.org/A258107


0

Saw this Question Late , Anyways i recognised a pattern Take an iterator with initial value 1 , count upto n (initial value = 1). While counting repeat every number < n, n times so , i=1 and n=1 1 i=1 , n=2 1 2 i=1 , n=3 1 2 2 3 i=1 , n=4 1 2 2 3 3 3 4 i=1 , n=5 1 2 2 3 3 3 4 4 4 4 5 So answer is 3 , 3 , 4 , 1


3

The missing numbers are To find them, observe that


3

I will guess that it is My reasoning is that


3

My answer: Below is Meant as comment, but alas @John S posted the following in a comment at https://puzzling.stackexchange.com/a/83526/60039 It is missing data. However: Also:


7

The odd one out is the This is because Safe Cracked!


3

Well, let me try... So, the next one should be...


0

Is the code I'm going to call the students A and B, and their numbers a and b.


0

Answer: Because: ...if that makes any since!


0

Answer Same reason as @Lonewolf Except: Edit: @kugo2006 posted his answer at the same time I was typing and I didn't notice 'til now that Lonewolf also corrected his


1

Answer: Because: EDIT: @Lonewolf corrected his at the same time I posted this!


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