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The answer maybe: The reason is:


I think number in sequence is : Reasoning :


So it looks like Which means the next two numbers are (I think)


I think the answer would be: Reasoning:


The next one is because each line is Read it like this:


The answer is Reason


The next number in the first sequence is Reasoning The next number in the second sequence is Reasoning


It follows So,


6 = As the sequence is


The rule is: Thanks to @Stiv, we also know that: Starting with 0: You can't go further because This may not be all there is to it though.


How many rabbit maximum would Roger have after a year from the adoption of his pets? How exactly can I find the number of rabbits in this situation? For this situation, I would just write it down. There are only four steps to take (4 quarters in a year), thus not much work to write it down. The growing rate is exatcly the same for the female as for the ...


As the number of rabbits added is thrice that of the original, the population of rabbits is quadrupled every 3 months. As such the growth can be modelled by $4^{(n/3) + 1}$, where n is the time in months after the first adoption. This can also be done iteratively as such: 0 months: 2F, 2M 3 months: 2F, 2M + 2(3F + 3M)...


The rule is: Question 1: Question 2: Question 3:


If we insert then the resulting sequence Where do these numbers come from? Well, We would then continue with


The answer is: Reason:


To add on to tansy's answer,


I found it's It's sequence where


The next number in the sequence is: The sequence he is following is:


Partial Answer I think this puzzle is related to: Partial Examples $(39 = 65 = 68 = 70 \approx 67) \subset 69 \mapsto 90$ $2 < 80 < 52 < (58 \approx 46) < 92 < 93 \le 94$ The remaining examples, FYI: Question (Unsolved) $\text{75 and 34, where are they?}$ Bonus Question $37 \approx 55 \land 37 \ne 55, \text{why}?$


The rule is: The missing 7 digits are:


I can understand part of what's happening. It has three groups of digits. We are seeing the second and third groups. Third Group The third group is counting: 50, 65, 85, 00, 15, 35, 50, 65, 85, 00, 15, 35, 50, 65, 85, 00, 15, 35, This is a fraction counting by $1\over6$, rounded to the nearest 0.05. This part is displayed except when the value is 00 ...

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