New answers tagged

4

I believe @Adam already found the correct solution, but I may have some new ideas concerning the pattern:


2

I’m going to start out with Now, @Bass’ Perl code So at least Therefore


2

Whenever I see a question like this, I imagine there is unlimited formulas to cover each optional (randomly) selection of those numbers in any direction, and if there isn't any other limiting rules, every answer to that question is correct. take a look at this


10

The series should be: Because: So the answer is: Note that:


5

My guess is: Nevertheless, I don't know where this puzzle comes from but that won't be surprising you are right and your friend may have made a mistake... Unless PSE community finds a simplier solution :)


10

First, we should determine what the sequence is. Now, does a 6 ever appear in this sequence? Quick detour Back to the show


2

I'll go with: Since the sequence seems to be


0

Answer: Idea similar JonMarkPerry, but slightly different, my guess: RULES: 1)BOLD NUMBER = BOLD NUMBER +2 2) right number is multiple of first two in a row multiply by number of simple divisors of each number(beginning one, not+2) different from it (EX for 3 is 1, 4 is 2 and 1, for 6 is 3 and 2 and 1 and so on) 3)right number is not bold only ...


0

My solution is... $l = left$ $r = right$ So the next number is: (I thought that the bold numbers doesn't matter)


0

My guess: because:


3



3

Solution 1 - expected solution Solution 2 - uses known Fibonacci list Step 1: Step 2: Step 3: Step 4: Step 5:


1

The answer is


4

Answer is: Giving: Logic:


1

It can be assumed that evaluation is left to right (or rather: clockwise), not by precedence rules. Then this reads and simplifies to or


3

Maybe, oeis will help me..oh no.. this puzzle is spoiled Answer is: Key to this is:


2

There's nothing wrong with @hexomino's answer, but it may be worth adding that Highbrow explanation for why: Now, Note:


4

The sequence satisfies the recurrence relation So the next number in the sequence, for example, is


3

This could relate to 19 101 920 20009 701 104 403 311 3000000000000000004


4

Answer Reasoning


2

I get


1

The answer could be: Because:


9

Building on the observation by rhsquared, the next number is Reasoning


5

(Partial) It looks like all the numbers are


3

The answer is The reason is:


11

I think x is: The pattern seems to be: Example: Therefore x is:


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