37

Final answer is or perhaps I should say I confess that I only bothered going this far by strict logical inference before allowing myself to make the obvious assumptions about the structure of the solution, leading to this (where white and yellow should now be treated as equivalent): whereupon it's clear how to get to the solution at the top.


22

Gareth McCaughan solved this, but here's an animation of the solution:


19

I think the answer is Completed Nonogram Traversed Maze


16

Answer is (Note: I see that Weather Vane posted a partial while I was working on this, but obviously I didn't look at their answer.)


16

nonogram: this is depicting


14

I think that the answer to the maze and nonogram is this:


14

The shapes are The filled grids are You get the shapes by


13

as Weathervane said, here is the crossword Then Finally


13

The solution to the nonogram: Next: And finally:


13

Completed Nonogram: Rebus decoding and final solution:


13

I think this is right! Doing this by hand was a real pain :)


12

Gladys is visiting The full nonogram: And if we split and rearrange like this: Then


12

oops just realised some mistakes: 1) row 252: 5 chunk should shift right for one block 2) first row of FRANCE: first grey block should shift right for one block


12

Step 1: Solving the nonogram: Step 2: Transcription to Blender: Step 3: Interpretation: Step 4: Separation:


11

Gladys is The grid: Transcription:


11

The completed nonogram is: Which appears to be In 3D the view looks like - Blue: Orange: Green: Purple: Red: All together: I would recommend


11

I think the answer is this Explaining $16$ possible solutions Some notes on how the solution is obtained.


10

Step 1 - the crossword Step 2 - trying to figure out the other numbers and arrows.


9

It's a The filled-in cells say (not perfectly clearly) Actual filled-in image:


9

(I did this without looking at the CW. I claim no credit for imposing arbitrary restrictions on myself, but it means any mistakes are my own :-).) The final grid is as follows: which obeys the following constraint: If we interpret we get "First", "Second", etc., are of course When groups of cells are referred to collectively, Note: in the course of ...


8

Pretty sure the answer is


8

This satisfies the requirements: I've provided a decimal conversion row and highlighted the locations of 11s in the "clue".


8

The grid looks like a game of Descartes Enigma - perhaps that's where you found it on your computer? The numbers labelling each row and column give the pattern of black cells in each row or column; different numbers correspond to groups of black cells which must have white cells in between. The grid is $15\times21$, so we can fill in a few sets of black ...


8

Absurdly partial answer Terminology: an "inner configuration" is an arrangement of filled and empty cells in our $n\times n$ grid; an "outer configuration" is the corresponding arrangement of run-lengths displayed outside the grid. Let $I_n=2^{n^2}$ be the number of possible inner configurations, $O_n$ be the number of distinct outer configurations arising ...


8

Pictured in the nonogram are ... The nonogram:


8

Here is the solution to the puzzle (note the correction in "3,1,2,5" to "3,1,2,1,4", by comment here):


7

Gladys is at: Solution to Nonogram: Details:


7

The 5-letter word is Cyan nonogram: Red nonogram: Both overlapping:


7

Nonogram solution: and with the Eye of Faith we can see that


6

@humn, can you please check this, but I contend that there is no valid semiminibinononohohohologram. First, we will prove that there is no row count of 0. If there existed such a row count, consider the group of 3 rows that the row labelled by it is in. Since both 0's and 1's take up all three rows, there cannot exist any 0's or 1's in the group of 3 rows, ...


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