New answers tagged

7

First steps first: we need to not get caught instantly. The only way to do that is to juke the Stickotaur into the top right corner. To do that, we must poke our head up on the first row, and eat an apple to get the rhythm correct. We can choose either of the top two apples in column 4. To keep things simple, let's choose the apple on row 2. Then, we are ...


3

It's Note that and then just


6

There is one solution for $G$, which is as follows Notice first that Now Suppose instead


7

I have the same final answer as the others, but using only one repeated method, namely This gives the following first step


1

I came up with the same solution as the other answers, but I did it a different way The solution: Steps: Edit: I realized that this method is not guaranteed to work.


5

Step 1: Step 2: Step 3: Step 4/solution:


6

Solution: Deduction process:


3

The answer is because For instance,


5

Here’s my solution. As far as I can tell, the crack at the bottom is just a discrepancy in my drawing. Neater version:


4

Here's how I reasoned through this before posting it. Others' methods turned out to be much simpler, though: Looking back, I think I know why my solution is longer now: I was originally going to specify that there must be three numbers in each group in the description, but I realized this would make the puzzle too easy. I then grafted steps to derive that ...


5

There is still another way:


16

Yet another way:


7

Another way:


17

The only possibilities are: Proof:


9

EDIT: Finished product first. For the logic on how to get there, read on. Let's start by figuring out the general steps, without taking the action limit into account. Obviously, we need to start by trapping the Stickotaur by taking a step right. Now we can clean the bottom 5 rows safely. Then, we can eat the apple in the top left (that seems to be the ...


2

Not an answer, but I would like to share my initial approach, before I figured that it's as helpful as I thought it was going to be. The idea for this kind of problem usually is to convert it into a graph, then usually its easier to visualize the solution. But not for this case, apparently. In the graph below, each node represents a square, and the edges ...


8

loopy walt beat me to the punch while I was editing the image. Here it is anyway (with a different order of moves):


14

It is Replay


3

105-move solution similar to Lukas', check his answer for the reasoning behind the major steps:


9

With the new edit removing the optimization constraint, I'll give it a shot. I am not sure if my solution conforms 100% with the rules, since there are some parts that seem real cheaty but nonetheless obey the rules in my eyes. First step: Second step: Third step: Forth step: Fifth step: Sixth step: Seventh (last) step: Edit:


24

The expression can be written as The key insight is that $\sqrt[12]{2}$ is This means the seventh power of this corresponds to Therefore,


2

My inner little sister can do it in Replay Not sure this is optimal, though. Bonus answer is given as a variation.


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