First, We then In fact, Alright, Because the question is modified,


We observe that As we have x = 2^1234567, we can try to plug it in. We will use the prime factorization of the numbers to make things easier. Next, We notice that This leaves us in the same place as the beginning, except Because none of the denominators have a factor of 3, We notice that We see that This means we just need to find the last 3 digits ...


Solution for b) The answer is Demonstration:


Partial Answer Solution for a): Process for a):



Yes, confirmed, here is how: It remains to verify:

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