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4 votes
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How do I solve this unreasonable 6x6 game of Towers without backtracking?

Column 5, Row 1: Also: Therefore: Hint for continuation:
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0 votes

Logical puzzle from a math homework for Russian fifth-year school students

could be just 52 - 44 = 8 26 - 25 = 1 11 - 2 = 9 so 8 + 1 = 9
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  • 1
0 votes

spinning disc camera

With only one (fixed position) camera, it seems to be impossible to determine which way the disk is spinning: The sensor will go from black to white (or white to black), as the delineation crosses the ...
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12 votes
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Help! Help! My IQ!

Here is the completed grid: How can we get there, Now, Wait, is that all? We saw some red dots in the sketch. What was that? Oh! Thanks. Nice puzzle by the way :)
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  • 370
3 votes

The children of the sultan

Let number of single births be W twin births be X triplet births be. Y quadruplet births be Z Therefore, total number of children = W+2X+3Y+4Z Let us assume that no other ...
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0 votes

Are there eighteen or twenty bars in my castle?

For those confused why the two day solution doesn't work please see the below: Day 1 Mark's perspective Mark 12 Rose 6 8 Rose knows Mark has one of 10 12 14 If I had 14 I would say 20. If I had 10 I ...
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2 votes
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Diversified Rubik's Cube

Each color appears $9$ times total, so an average of $9/6$ times per face, which implies a lower bound Without loss of generality, color $c$ appears at the center of face $c$. Here is such an ...
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4 votes
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Conclusively solving the extreme gerrymandering puzzle

The answer, in short: Now let's take a look at why: Now, we can show that Thus,
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2 votes

Solving Sudoku purely by logic: why does this X-cycle choose this cell?

For me, this one is easier to see if I start with simple alternation elsewhere. Let's consider all the squares where 4 is still a possibility: I can see that there are a number of rows and columns ...
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Ten Pills in Ten Countries

Total cost of
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2 votes

Ten Pills in Ten Countries

Here is my answer with all pills are inside the bottles. as ( Pills - Bottles)
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0 votes

Ten Pills in Ten Countries

First of all it would be necessary for OP to confirm whether or not: In that case the answer would be simply $0 I'd argue that the answer is $500: Here I'd take a modified approach to what loopy ...
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-2 votes

Ten Pills in Ten Countries

I may have misread the question, but total cost: Simply:
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-3 votes

Ten Pills in Ten Countries

Not sure if but if not, then Making the grand total $0.
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  • 95
0 votes

Ten Pills in Ten Countries

total cost: 700 1 unlabelled unbottled pill 1 unlabelled bottled pill 2 pills in an unlabeled bottle with a '1' label on one pill 2 pills in a bottle with a '1' label on the cap and a '1' label on ...
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6 votes

Ten Pills in Ten Countries

This is probably not the intended answer, but how about this: slight variation: Another variation, which is my favourite:
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3 votes

Ten Pills in Ten Countries

I think it's fair to say this is optimal:
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1 vote

Ten Pills in Ten Countries

Total cost:$200 How? Cut sticker number 2 into 9 equal parts and distribute to 9 bottles except the first one
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12 votes

Ten Pills in Ten Countries

Total cost: How? When consumed in the order listed there will never be ambiguity.
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3 votes

Ten Pills in Ten Countries

First off, one bottle can be For the rest, we can All in all:
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11 votes
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Online Quilt Pattern Design Contest

Placements: Entry: So For the rest
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2 votes

Church charity lottery

This question has been answered fairly. However, I want to point out that an algorithmic way of answering it, could be used. Indeed, Let $\xi(n, m)$ be the maximum amount obtained using exactly $n$ ...
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  • 121
2 votes

A logic puzzle with some lateral thinking

Question 1 - "Which one of you is Aaron?" #1 is not Aaron. #1 is Aaron. #3 is not Aaron. (stays silent) Question 2 - "Who was #2 with during the crime?" #2 was with #1 during ...
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  • 515
10 votes
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Objects in Mirror

Final grid: Step 1: First steps Step 2: Progression Step 3: Intersections Step 4: A quadruplet breakthrough Step 5: Falling like dominoes Step 6: Finishing touches
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1 vote

A logic puzzle with some lateral thinking

The "rules" here seem bendy enough that I'm not sure this is correct and/or the only possible solution, but it seems like it could be the case that: My reasoning is that:
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