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75

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18

The property is that


15

I believe the answer is Reasoning:


13

I have found this solution


12

This is the line of thought I followed: Statement #3 As a consequence, If #4 were true, then #2 must be true (by exclusion), but this would imply that #4 itself is false. Then, If #5 were true, Accordingly, In conclusion,


11

For clarify: No matter who you ask, he will answer the correct door.


11

Solution: Edit:


10

The property seems to be related to: Explanation: So the property is, Or The title (Thanks to @trolley813): Old (and wrong) answer The property is: And,


10

Could this be @Oray found another one, which might possibly be


9

This feels a bit underdetermined to me, probably meaning that I'm missing some hidden hints that nail things down further. But here's one thing we can do, which meets the explicitly given requirements: where we take


9

Ask the following question of all three guards: Now the number of Yeses (Y) will be between 0 and 3 inclusive. If Y=1, go through that door. The position may either be 1. in which case you go to heaven, or it may be one of in which case you go to hell. If Y=2, namely 3. then pick one of the Yeses at random and ask the utterer the same question again. ...


8

True statement is Reason


8

Is it Thus we have Other letters don't share this property because For the newer hints


7


7

Another nice way to approach this puzzle is by constructing chains of implications. We know there's only one true statement, so if one statement implies another one, then it's false.


7

The colors are The rules are


7

7S can be forcibly won with five HCP: . ♠8765432/-/♦765432/- ♠K/♥AK/♦AKQJ/♣AKQJT9 ♠Q/♥QJ/♦T98/♣8765432 . ♠AJT9/♥T98765432/-/- If West leads a spade, South takes the ace. If West leads a heart, North ruffs and leads a spade to the ace. Otherwise South ruffs low and leads the ace of spades. South ...


6

Here's why: Imagine the family tree of such a population. It might look something like this a <------Generation A - one person b b b ccc ccc ccc <------Generation C - nine people The solution to the paradox is that By shifting the burden by one generation back, Also, it is important to consider the following If they are ...


6

Either that's a coincidence or Im guessing that's the pattern that cracks the code? Pretty interesting.


6

I'd go with this: Special thanks to @Amorydai for their valuable feedback in comments If it is Michel If it is Vlad If it is John So


6

I think it's: This means that:


5

The key fact is as follows: Therefore this particular game ends when the numbers on the board are So the conclusion is


5

Some grids for question 1: 44 circles 45 circles 45 circles


5

(Assisted 7NT): Given optimal card distribution, just have the opponents discard the high cards: (Assisted 7♠): The ♠A can eat ♠K and ♠Q at most, so we must also have the ♠J, for a total or (Guaranteed 7NT): First answer, which assumed that I cannot arrange the opponents' cards. (Guaranteed 7NT): Edited in after OP clarified that I get to arrange the ...


5

Let's call everyone by their initial, except that since there are two As we'll use N for Alyin and A for Alayna. Then the answer is Derivation: If you want to check my work, put the following into a Python interpreter and verify that you get a bunch of Trues out (I do):


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