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Alain Remillard has given the mathematician's answer. Here's the physicist's one:
Step 1:
Obviously, in such a universe, regardless of their speed, the cannonballs will travel in a straight line and hit each other in the middle.
Step 2:
Assume "Step 1" does not exist.
Therefore
19
Here is a solution that works in the general case of two squares of any size placed next to each other.
18
A slightly different graphic:
12
11
They will
I did it mathematically
Suppose the horizontal distance between both cannons is $d$ and the up
angle from right cannon is $\theta$. Then, the left cannon is at a
height of $d\tan\theta$ and aim down at an angle of $\theta$. Since
the horizontal speed of the cannonballs are the same, there is à time
when they are both at the same ...
5
Well, judging from the hint, each $[m\ast n]$ means
In our case, we seem to have only $[n\ast n]$, in which case
So rewriting all the expressions we've been given:
Word 1 (2 letters): $[3*3]+[1*1]+[2*2]+[2*2]$
Word 2 (5 letters): $((-[1*1] + [3*3] + [4*4] + [8*8] + [27*27]) \cdot [2*2] + [1*1] + [1*1] + [5*5] \cdot [27*27]) \cdot [2*2]$
Word 3 (2 ...
3
The answer is most likely
Because
2
I hopped onto google drawings to make the sketch you asked for. If all you want is the boundary than making a hexagon is very simple. I feel like I am missing some aspect of this...
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