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Alain Remillard has given the mathematician's answer. Here's the physicist's one: Step 1: Obviously, in such a universe, regardless of their speed, the cannonballs will travel in a straight line and hit each other in the middle. Step 2: Assume "Step 1" does not exist. Therefore


19

Here is a solution that works in the general case of two squares of any size placed next to each other.


18

A slightly different graphic:


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They will I did it mathematically Suppose the horizontal distance between both cannons is $d$ and the up angle from right cannon is $\theta$. Then, the left cannon is at a height of $d\tan\theta$ and aim down at an angle of $\theta$. Since the horizontal speed of the cannonballs are the same, there is à time when they are both at the same ...


5

Well, judging from the hint, each $[m\ast n]$ means In our case, we seem to have only $[n\ast n]$, in which case So rewriting all the expressions we've been given: Word 1 (2 letters): $[3*3]+[1*1]+[2*2]+[2*2]$ Word 2 (5 letters): $((-[1*1] + [3*3] + [4*4] + [8*8] + [27*27]) \cdot [2*2] + [1*1] + [1*1] + [5*5] \cdot [27*27]) \cdot [2*2]$ Word 3 (2 ...


3

The answer is most likely Because


2

I hopped onto google drawings to make the sketch you asked for. If all you want is the boundary than making a hexagon is very simple. I feel like I am missing some aspect of this...


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