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Answer to theonlygusti 's Clue I hope this is how it's done. Edit by Rosie F (Rather than posting a comment, I edit the answer, so that I can hide the spoiler) There is also the solution

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Answer to Gareth's Clue I hope this is how it's done.

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Ok, the only solution I know for this one is extremely surprising as it really forces you to think outside of the box. Use $1,3,4,6$ and any of the arithmetic operators to make $24$. Trust me, the solution I've seen is really beautiful :)

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[I hope I'm understanding the intended procedure correctly: an answer here is meant to be a question, to be answered by an answer to the "robbers" question. Right?] My personal favourite 24-puzzle sounds very simple but is surprisingly tricky: make 24 from the numbers 3,3,8,8, using only arithmetic operations.

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Given a line segment radius R, find a point that is exactly R away from one endpoint of the segment, and lies on the same vector. Draw two circles of radius $R$ about the two ends of the line segement $a$ and $b$. Call the circles $A$ and $B$. They meet at two new points $c$ and $d$. $c$ and $d$ are $\sqrt{3}R$ from each other. Draw a circle of radius \$\...

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From the Cop's challenge thread: https://puzzling.stackexchange.com/a/25330/13101 OK, I've got an easy one to start with. Given a line segment radius R, find a point that is exactly R away from one endpoint of the segment, and lies on the same vector. Essentially, double the line segment. Answer: Image:

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OK, I've got an easy one to start with. Given a straight line segment radius R, find a point that is exactly R away from one endpoint of the segment, and is colinear with the two endpoints. Essentially, double the line segment.

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